[R] Error on using Confint function to calculate 95% CI

[Michael Dewey]

I am afraid your post is more or less unreadable since you posted in 
HTML and this is a plain text list.

It might also help if you gave more context like the full results of 
your model. There is a list dedicated to mixed models 
https://stat.ethz.ch/mailman/listinfo/r-sig-mixed-models
which may be able to help you better.

Michael

On 26/04/2023 02:37, bharat rawlley via R-help wrote:
> Hello,
> 
> I am trying to estimate 95% CI using the confint function for a generalized liner model. While I am able to estimate Odds ratio using the coef function but on using the confint function, I get the message " Error in approx(sp$y, sp$x, xout = cutoff) : need at least two non-NA values to interpolate"
> The following are the Coefficients for which I am trying to calculate 95% CI.
> The original data has no NA values so I am not sure why this error is showing up
> Estimate Std. Error z value Pr(>|z|)1.05649 0.30658 3.446 0.000569 ***-0.58348 0.49948 -1.168 0.242744-0.77959 1.47292 -0.529 0.596609-18.50414 6522.63862 -0.003 0.997736-0.82328 0.49102 -1.677 0.093608 .-13.95852 4036.00271 -0.003 0.9972410.53909 0.83073 0.649 0.516376-0.55514 0.46189 -1.202 0.22940817.75434 6522.63863 0.003 0.997828-15.97188 1051.20492 -0.015 0.987878-0.16589 0.43172 -0.384 0.70079231.60387 1459.11421 0.022 0.982719-0.42616 0.43637 -0.977 0.3287661.10179 1.19697 0.920 0.3573210.52345 1.23113 0.425 0.6707050.50791 1.54670 0.328 0.7426210.19881 0.34945 0.569 0.569403-0.07887 0.49769 -0.158 0.8740850.05958 0.36780 0.162 0.871306-0.61339 0.38503 -1.593 0.111142
> I tried to compute 95% CI using the above coefficients using the cofit function
> Thank you!
> 
> 
> 
> 	[[alternative HTML version deleted]]
> 
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-- 
Michael
http://www.dewey.myzen.co.uk/home.html