[R] automatic convert list to dataframe

Kai Yang y@ngk@|9999 @end|ng |rom y@hoo@com
Mon Oct 3 19:38:43 CEST 2022

 Hi Rui,
list2env(file1, envir = .GlobalEnv) is worked very well. Thank you.

But when I tried to put the sample code  into for loop. I got error message:
for(i in filenames){
  assign(i, import_list(paste0(i, ".xlsx", sep="")))
  names(i) <- paste(i, names(i), sep = "_")
  list2env(names(i), envir = .GlobalEnv)
Error in list2env(names(i), envir = .GlobalEnv) :   first argument must be a named list

It seems I cannot put names(i) into for loop, Could you please help me to debug it?
Thank you,Kai    On Monday, October 3, 2022 at 10:14:25 AM PDT, Rui Barradas <ruipbarradas using sapo.pt> wrote:  

list2env(file1, envir = .GlobalEnv)

will create data.frames dx1, dx2, etc, in the global environment.
If you really need the names file1_dx1, file1_dx2, etc, you can first 
change the names

names(file1) <- paste("file1", names(file1), sep = "_")

and then run list2env like above.

Hope this helps,

Rui Barradas

Às 16:51 de 03/10/2022, Kai Yang via R-help escreveu:
> Hi R team,
> I can use rio package to read excel file into R as a list. The excel file content multiple sheets (30 - 40 data sheets). I can convert each data elements into dataframe manually. I have multiple excel files with multiple data sheets. I need to load them into R and do the comparison for same sheet name from difference excel file. My current code is:
>  library(rio)   setwd ("C:/temp")
> filenames <- gsub("\\.xlsx$","", list.files(pattern="\\.xlsx$"))
> for(i in filenames){
>    assign(i, import_list(paste0(i, ".xlsx", sep="")))
> }
> file1_dx1     <-  file1[["dx1"]]
> file1_dx2     <-  file1[["dx2"]]
> file1_dx3     <-  file1[["dx3"]]
> file2_dx1     <-  file1[["dx1"]]
> file2_dx2     <-  file1[["dx2"]]
> ......
> I hope the code can automatic converting the list (may have 30 - 40 lists) by adding file name (such as: filename_sheetname) and put it in for loop
> Thank you,
> Kai
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