[R] How to improve accuracy of output?

Thierry Onkelinx th|erry@onke||nx @end|ng |rom |nbo@be
Tue May 24 16:04:24 CEST 2022

Dear Maithreyi,

You need to read FAQ 7.31. 0.99 and 0.9899999999999 are equivalent. And
their difference is most likely not relevant.

Best regards,

ir. Thierry Onkelinx
Statisticus / Statistician

Vlaamse Overheid / Government of Flanders
Team Biometrie & Kwaliteitszorg / Team Biometrics & Quality Assurance
thierry.onkelinx using inbo.be
Havenlaan 88 bus 73, 1000 Brussel

To call in the statistician after the experiment is done may be no more
than asking him to perform a post-mortem examination: he may be able to say
what the experiment died of. ~ Sir Ronald Aylmer Fisher
The plural of anecdote is not data. ~ Roger Brinner
The combination of some data and an aching desire for an answer does not
ensure that a reasonable answer can be extracted from a given body of data.
~ John Tukey


Op di 24 mei 2022 om 16:01 schreef maithili_shiva--- via R-help <
r-help using r-project.org>:

> Dear Forum
> In my code, I am trying to compute Value at risk.
> I have an issue as mentioned below:
> I have defined
> options(digits = 14)
> But my output is something like
> >  df$price
> [1] 98.7185273         103.10265923  ............
> However, if use Excel, I get values as
> 98.718527356108 103.10265923704
> and so on.
> Is there any way I can improve on R output accuracy.
> Problem is If I use
> options(digits = 20)
> I still get same prices as when I was using options(digits = 14) and on
> the other hand my confidence level value, which should be equal to 0.99,
> gets distorted to 0.989999999999 impacting  Value at Risk value.
> Please guide
> Regards
> Maithreyi
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