[R] Dplyr question

Richard O'Keefe r@oknz @end|ng |rom gm@||@com
Thu Jun 23 02:28:32 CEST 2022


Why do you want to use dplyr?
It's easy using base R.

original <- ...
a <- cbind(original[,-3], Location=colnames(original)[2])
colnames(a)[2] <- "Measurement"
b <- cbind(original[,-2], Location=colnames(original)[3])
colnames(b)[2] <- "Measurement"
result <- rbind(a, b)[,c(1,3,2)]




On Wed, 22 Jun 2022 at 04:23, Thomas Subia <thomas.subia using fmindustries.com>
wrote:

> Colleagues:
>
> The header of my data set is:
> Time_stamp      P1A0B0D P190-90D
> Jun-10 10:34    -0.000208       -0.000195
> Jun-10 10:51    -0.000228       -0.000188
> Jun-10 11:02    -0.000234       -0.000204
> Jun-10 11:17    -0.00022        -0.000205
> Jun-10 11:25    -0.000238       -0.000195
>
> I want my data set to resemble:
>
> Time_stamp      Location        Measurement
> Jun-10 10:34    P1A0B0D -0.000208
> Jun-10 10:51    P1A0B0D -0.000228
> Jun-10 11:02    P1A0B0D -0.000234
> Jun-10 11:17    P1A0B0D -0.00022
> Jun-10 11:25    P1A0B0D -0.000238
> Jun-10 10:34    P190-90D        -0.000195
> Jun-10 10:51    P190-90D        -0.000188
> Jun-10 11:02    P190-90D        -0.000204
> Jun-10 11:17    P190-90D        -0.000205
> Jun-10 11:25    P190-90D        -0.000195
>
> I need some advice on how to do this using dplyr.
>
> V/R
> Thomas Subia
>
> FM Industries, Inc. - NGK Electronics, USA | www.fmindustries.com
> 221 Warren Ave, Fremont, CA 94539
>
> "En Dieu nous avons confiance, tous les autres doivent apporter des
> donnees"
>
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