[R] How to globally convert NaN to NA in dataframe?
Andrew Simmons
@kw@|mmo @end|ng |rom gm@||@com
Thu Sep 2 15:47:06 CEST 2021
You removed the second line 'xx' from the function, put it back and it
should work
On Thu, Sep 2, 2021, 09:45 Luigi Marongiu <marongiu.luigi using gmail.com> wrote:
> `data[sapply(data, is.nan)] <- NA` is a nice compact command, but I
> still get NaN when using the summary function, for instance one of the
> columns give:
> ```
> Min. : NA
> 1st Qu.: NA
> Median : NA
> Mean :NaN
> 3rd Qu.: NA
> Max. : NA
> NA's :110
> ```
> I tried to implement the second solution but:
> ```
> df <- lapply(x, function(xx) {
> xx[is.nan(xx)] <- NA
> })
> > str(df)
> List of 1
> $ sd_ef_rash_loc___palm: logi NA
> ```
> What am I getting wrong?
> Thanks
>
> On Thu, Sep 2, 2021 at 3:30 PM Andrew Simmons <akwsimmo using gmail.com> wrote:
> >
> > Hello,
> >
> >
> > I would use something like:
> >
> >
> > x <- c(1:5, NaN) |> sample(100, replace = TRUE) |> matrix(10, 10) |>
> as.data.frame()
> > x[] <- lapply(x, function(xx) {
> > xx[is.nan(xx)] <- NA_real_
> > xx
> > })
> >
> >
> > This prevents attributes from being changed in 'x', but accomplishes the
> same thing as you have above, I hope this helps!
> >
> > On Thu, Sep 2, 2021 at 9:19 AM Luigi Marongiu <marongiu.luigi using gmail.com>
> wrote:
> >>
> >> Hello,
> >> I have some NaN values in some elements of a dataframe that I would
> >> like to convert to NA.
> >> The command `df1$col[is.nan(df1$col)]<-NA` allows to work column-wise.
> >> Is there an alternative for the global modification at once of all
> >> instances?
> >> I have seen from
> >>
> https://stackoverflow.com/questions/18142117/how-to-replace-nan-value-with-zero-in-a-huge-data-frame/18143097#18143097
> >> that once could use:
> >> ```
> >>
> >> is.nan.data.frame <- function(x)
> >> do.call(cbind, lapply(x, is.nan))
> >>
> >> data123[is.nan(data123)] <- 0
> >> ```
> >> replacing o with NA, but I got
> >> ```
> >> str(df)
> >> > logi NA
> >> ```
> >> when modifying my dataframe df.
> >> What would be the correct syntax?
> >> Thank you
> >>
> >>
> >>
> >> --
> >> Best regards,
> >> Luigi
> >>
> >> ______________________________________________
> >> R-help using r-project.org mailing list -- To UNSUBSCRIBE and more, see
> >> https://stat.ethz.ch/mailman/listinfo/r-help
> >> PLEASE do read the posting guide
> http://www.R-project.org/posting-guide.html
> >> and provide commented, minimal, self-contained, reproducible code.
>
>
>
> --
> Best regards,
> Luigi
>
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