[R] how to include if conditions in dplyr filter function

[Avi Gross]

The error below was fairly clear. The R 'if" statement is not vectorized and
takes a single logical argument. It is not normally used in a pipeline
unless at that point the data has been reduced to a vector of length 1.

I do not want to look at your code further without the data behind it but
suggest there is a vectorized ifelse() function that might fit your needs
but since you use filter(0 so many times in there, maybe this should not be
one long pipeline.



-----Original Message-----
From: R-help <r-help-bounces using r-project.org> On Behalf Of Yuan Chun Ding via
R-help
Sent: Tuesday, October 26, 2021 6:39 PM
To: r-help using r-project.org
Subject: [R] how to include if conditions in dplyr filter function

Hi R users,

I thought the follow R code should work, but I got error, Can you fix my
code?

Thank you,

Ding


outlier_tcga_MAD3 <- outlier_tcga %>% filter(n_two >0) %>% 
      mutate(freqMAD3_gain2ratio = N_MAD3_gain2/n_two )%>%
  if (N_MAD3 < 9) {filter(freqMAD3_gain >=1)} else if (N_MAD3 > n_two*2 )
                  {filter (freqMAD3_gain >= 0.8 & freqMAD3_gain2ratio >=
0.33)} else 
                  {filter(freqMAD3_gain2 >=0.3 )} %>%
  arrange(desc(N_MAD3))


Error in if (.) N_MAD3 < 9 else { : 
  argument is not interpretable as logical In addition: Warning message:
In if (.) N_MAD3 < 9 else { :
  the condition has length > 1 and only the first element will be used

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