[R] Some difficulties to use the apply command on an array

[Laurent Rhelp]

Thank you for the explanations. Indeed I made a mistake for the MARGIN 
understanding. But when I use the command I have an error because there 
is no simplify argument in the apply command ?




Le 05/07/2021 à 17:05, Andrew Simmons a écrit :
> Hello,
>
>
> It seems as though you may be using `MARGIN` incorrectly. `MARGIN` is 
> the indices you are looping through, so it should be MARGIN = 1, not 
> MARGIN = c(2, 3). Additionally, you probably want to set argument 
> `simplify` to FALSE. Something like
>
> apply(x, 1, FUN = function(x) diag( svd(x)$d ), simplify = FALSE)
>
> seems to work well for me. I hope this helps!
>
> On Mon, Jul 5, 2021 at 10:56 AM Laurent Rhelp <LaurentRHelp using free.fr 
> <mailto:LaurentRHelp using free.fr>> wrote:
>
>     Dear R-Help,
>
>     I have an array x made up of three matrices of 5 rows and 3
>     columns of
>     complex numbers (the complex numbers are not the problem)
>
>     ## my array
>     x <- structure(c(5.6196790161893828+0i, 5.7565523942393364+0i,
>     8.5242834298729342+0i,
>                    10.304766710160479+0i, 11.412967010108229+0i,
>     -2.6952197604866495-5.7324226520260237e-18i,
>                    -3.8053698833683476-1.5535793240880411i,
>     -4.440850591952894-0.21277190153473785i,
>                    -4.9049897326853316+0.22487294128201613i,
>     -4.6982778900868931-0.35986943359186585i,
>                    -6.7722948827866034-1.8252881225149525e-16i,
>     -5.6864255243941733-0.82149125972147463i,
>                    -2.5321753317962115-3.4309121438578525i,
>     0.85377696343414344-4.3720244641138883i,
>                    6.3363344379954638-2.23654533694011i,
>     -2.6952197604866495+5.7324226520260237e-18i,
>                    -3.8053698833683476+1.5535793240880411i,
>     -4.440850591952894+0.21277190153473785i,
>                    -4.9049897326853316-0.22487294128201613i,
>     -4.6982778900868931+0.35986943359186585i,
>                    3.1683154084671417+0i, 5.397392162921844+0i,
>     8.3085887222115922+0i,
>                    11.150391891976289+0i, 13.173434845070231+0i,
>     3.7978840709983359+5.0735539531499429e-17i,
>                    3.0599215005995717-2.3669737981128267i,
>     0.5951827523696811-3.2116907301709845i,
>                    -1.7735244105472532-3.8366652813316566i,
>     -5.0558348297797169-2.6645747173403049i,
>                    -6.7722948827866034+1.8252881225149525e-16i,
>     -5.6864255243941733+0.82149125972147463i,
>                    -2.5321753317962115+3.4309121438578525i,
>     0.85377696343414344+4.3720244641138883i,
>                    6.3363344379954638+2.23654533694011i,
>     3.7978840709983359-5.0735539531499429e-17i,
>                    3.0599215005995717+2.3669737981128267i,
>     0.5951827523696811+3.2116907301709845i,
>                    -1.7735244105472532+3.8366652813316566i,
>     -5.0558348297797169+2.6645747173403049i,
>                    8.5581082281979697+0i, 8.6908832216086331+0i,
>     12.394094469562258+0i,
>                    16.106350896659897+0i, 19.569513600539693+0i), .Dim =
>     c(5L, 3L,
>     3L))
>
>     str(x)
>     #  cplx [1:5, 1:3, 1:3] 5.62+0i 5.76+0i 8.52+0i ...
>
>     The dimensions (i,j,k) of my array are 5, 3, 3. For every value of
>     i, I
>     am interested in the squared matrices made up of the j columns for
>     all
>     the k indice. For a given value i I have to keep the row i for
>     every k.
>     For example if i=1, I am interested by the matrix x[1,,]
>     ##
>     x[1,,]
>
>     ##              [,1]         [,2]         [,3]
>     ## [1,]  5.619679+0i -2.695220+0i -6.772295+0i
>     ## [2,] -2.695220-0i  3.168315+0i  3.797884-0i
>     ## [3,] -6.772295-0i  3.797884+0i  8.558108+0i
>
>     Now, for every value of i, I want to calculate the SVD
>     decomposition and
>     get the diagonal matrix created by the singular values. When I set
>     the i
>     value it works:
>     diag( svd(x[1,,])$d )
>
>     # [,1]     [,2]      [,3]
>     # [1,] 15.73833 0.000000 0.0000000
>     # [2,]  0.00000 1.502771 0.0000000
>     # [3,]  0.00000 0.000000 0.1049992
>
>
>     But when I try to do a loop on the i value it doesn't work:
>
>     apply(x, c(2,3), FUN = function(x) diag( svd(x)$d ))
>
>
>     # [,1]        [,2]        [,3]
>     # [1,] Numeric,361 Numeric,81  Numeric,144
>     # [2,] Numeric,81  Numeric,400 Numeric,81
>     # [3,] Numeric,144 Numeric,81  Numeric,900
>
>     I do not understand how to do the apply on an array in order to
>     get my
>     diagonals matrices. I think that I miss something about the
>     understanding of the array object.
>
>     Thank you for your help
>
>     Laurent
>
>
>
>
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