[R] replace zero in a matrix using random numbers

Rui Barradas ru|pb@rr@d@@ @end|ng |rom @@po@pt
Fri Jan 8 23:44:53 CET 2021


Try to get the number of zero values before:

i <- er.miRCounts == 0
n <- sum(i)
er.miRCounts[i] <- rnorm(n,mean=1, sd=0.1)

Also, there is no need for a end-of-instruction ';'.
The semi-colon is the instruction separator, so if you put it at the end 
you will be separating the instruction you wrote from the NULL 
instruction. A simpler example could be


This is *two* instructions:

mean(1:5); NULL

Hope this helps,

Rui Barradas

Às 22:33 de 08/01/21, Yuan Chun Ding escreveu:
> Hi R users,
> I am analyzing miRNA sequence data for a special network analysis, I need to replace zero values in a matrix as random numbers with mean of 1 and standard deviation of 0.1.
> er.miRCounts[er.miRCounts==0] <- rnorm(1,mean=1, sd=0.1);
> this code made all zero values as 1.13, not random numbers across different zero values.  If all zero values in one row are replaced by the same 1.13,  then sd in that row is zero, causing other problem in the following calculation.
> Can you help me?
> Thank you,
> Yuan chun Ding
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