[R] Defining partial list of variables

Heinz Tuechler tuech|er @end|ng |rom gmx@@t
Tue Jan 5 13:49:37 CET 2021


What about the Cs()-function in Hmisc?
library(Hmisc)
Cs(a,b,c)
[1] "a" "b" "c"

Steven Yen wrote/hat geschrieben on/am 05.01.2021 13:29:
> Thanks Eric. Yes, "unlist" makes a difference. Below, I am doing not
> regression but summary to keep the example simple.
>
>  > set.seed(123)
>  > data<-matrix(runif(1:25),nrow=5)
>  > colnames(data)<-c("x1","x2","x3","x4","x5"); data
>              x1        x2        x3         x4        x5
> [1,] 0.2875775 0.0455565 0.9568333 0.89982497 0.8895393
> [2,] 0.7883051 0.5281055 0.4533342 0.24608773 0.6928034
> [3,] 0.4089769 0.8924190 0.6775706 0.04205953 0.6405068
> [4,] 0.8830174 0.5514350 0.5726334 0.32792072 0.9942698
> [5,] 0.9404673 0.4566147 0.1029247 0.95450365 0.6557058
>  > j<-strsplit(gsub("[\n ]","","x1,x3,x5"),",")
>  > j<-unlist(j); j
> [1] "x1" "x3" "x5"
>  > summary(data[,j])
>         x1               x3               x5
>   Min.   :0.2876   Min.   :0.1029   Min.   :0.6405
>   1st Qu.:0.4090   1st Qu.:0.4533   1st Qu.:0.6557
>   Median :0.7883   Median :0.5726   Median :0.6928
>   Mean   :0.6617   Mean   :0.5527   Mean   :0.7746
>   3rd Qu.:0.8830   3rd Qu.:0.6776   3rd Qu.:0.8895
>   Max.   :0.9405   Max.   :0.9568   Max.   :0.9943
>
> On 2021/1/5 下午 07:08, Eric Berger wrote:
>> wrap it in unlist
>>
>> xx <- unlist(strsplit( .... ))
>>
>>
>>
>> On Tue, Jan 5, 2021 at 12:59 PM Steven Yen <styen using ntu.edu.tw
>> <mailto:styen using ntu.edu.tw>> wrote:
>>
>>     Thanks Eric. Perhaps I should know when to stop. The approach
>>     produces a slightly different variable list (note the [[1]]).
>>     Consequently, I was not able to use xx in defining my regression
>>     formula.
>>
>>     > x<-colnames(subset(mydata,select=c(
>>
>>     +    hhsize,urban,male,
>>     +    age3045,age4659,age60, # age1529
>>     +    highsc,tert,           # primary
>>     +    gov,nongov,            # unemp
>>     +    married))); x
>>      [1] "hhsize"  "urban"   "male"    "age3045" "age4659" "age60"
>>     "highsc"  "tert"
>>      [9] "gov"     "nongov"  "married"
>>     > xx<-strsplit(gsub("[\n ]","",
>>     +    "hhsize,urban,male,
>>     +     age3045,age4659,age60,
>>     +     highsc,tert,
>>     +     gov,nongov,
>>     +     married"
>>     + ),","); xx
>>     [[1]]
>>      [1] "hhsize"  "urban"   "male"    "age3045" "age4659" "age60"
>>     "highsc"  "tert"
>>      [9] "gov"     "nongov"  "married"
>>
>>     > eq1<-my.formula(y="cig",x=x); eq1
>>     cig ~ hhsize + urban + male + age3045 + age4659 + age60 + highsc +
>>         tert + gov + nongov + married
>>     > eq2<-my.formula(y="cig",x=xx); eq2
>>     cig ~ c("hhsize", "urban", "male", "age3045", "age4659", "age60",
>>         "highsc", "tert", "gov", "nongov", "married")
>>
>>     On 2021/1/5 下午 06:01, Eric Berger wrote:
>>>     If your column names have no spaces the following should work
>>>
>>>      x<-strsplit(gsub("[\n ]","",
>>>      "hhsize,urban,male,
>>>     + gov,nongov,married"),","); x
>>>
>>>     On Tue, Jan 5, 2021 at 11:47 AM Steven Yen <styen using ntu.edu.tw
>>>     <mailto:styen using ntu.edu.tw>> wrote:
>>>
>>>         Here we go! BUT, it works great for a continuous line. With
>>>         line break(s), I got the nuisance "\n" inserted.
>>>
>>>         > x<-strsplit("hhsize,urban,male,gov,nongov,married",","); x
>>>         [[1]]
>>>         [1] "hhsize"  "urban"   "male"    "gov" "nongov"  "married"
>>>
>>>         > x<-strsplit("hhsize,urban,male,
>>>         +             gov,nongov,married",","); x
>>>         [[1]]
>>>         [1] "hhsize"            "urban" "male"
>>>         "\n            gov"
>>>         [5] "nongov"            "married"
>>>
>>>         On 2021/1/5 下午 05:34, Eric Berger wrote:
>>>>         zx<-strsplit("age,exercise,income,white,black,hispanic,base,somcol,grad,employed,unable,homeowner,married,divorced,widowed",",")
>>>>
>>>>
>>>>
>>>>         On Tue, Jan 5, 2021 at 11:01 AM Steven Yen <styen using ntu.edu.tw
>>>>         <mailto:styen using ntu.edu.tw>> wrote:
>>>>
>>>>             Thank you, Jeff. IMO, we are all here to make R work
>>>>             better to suit our
>>>>             various needs. All I am asking is an easier way to
>>>>             define variable list
>>>>             zx, differently from the way z0 , x0, and treat are defined.
>>>>
>>>>              > zx<-colnames(subset(mydata,select=c(
>>>>             +
>>>>             age,exercise,income,white,black,hispanic,base,somcol,grad,employed,
>>>>             + unable,homeowner,married,divorced,widowed)))
>>>>              > z0<-c("fruit","highblood")
>>>>              > x0<-c("vgood","poor")
>>>>              > treat<-"depression"
>>>>              > eq1 <-my.formula(y="depression",x=zx,z0)
>>>>              > eq2 <-my.formula(y="bmi", x=zx,x0)
>>>>              > eq2t<-my.formula(y="bmi", x=zx,treat)
>>>>              > eqs<-list(eq1,eq2); eqs
>>>>             [[1]]
>>>>             depression ~ age + exercise + income + white + black +
>>>>             hispanic +
>>>>                  base + somcol + grad + employed + unable +
>>>>             homeowner + married +
>>>>                  divorced + widowed + fruit + highblood
>>>>
>>>>             [[2]]
>>>>             bmi ~ age + exercise + income + white + black + hispanic
>>>>             + base +
>>>>                  somcol + grad + employed + unable + homeowner +
>>>>             married +
>>>>                  divorced + widowed + vgood + poor
>>>>
>>>>              > eqt<-list(eq1,eq2t); eqt
>>>>             [[1]]
>>>>             depression ~ age + exercise + income + white + black +
>>>>             hispanic +
>>>>                  base + somcol + grad + employed + unable +
>>>>             homeowner + married +
>>>>                  divorced + widowed + fruit + highblood
>>>>
>>>>             [[2]]
>>>>             bmi ~ age + exercise + income + white + black + hispanic
>>>>             + base +
>>>>                  somcol + grad + employed + unable + homeowner +
>>>>             married +
>>>>                  divorced + widowed + depression
>>>>
>>>>             On 2021/1/5 下午 04:18, Jeff Newmiller wrote:
>>>>             > IMO if you want to hardcode a formula then simply
>>>>             hardcode a formula. If you want 20 formulas, write 20
>>>>             formulas. Is that really so bad?
>>>>             >
>>>>             > If you want to have an abbreviated way to specify sets
>>>>             of variables without conforming to R syntax then put
>>>>             them into data files and read them in using a format of
>>>>             your choice.
>>>>             >
>>>>             > But using NSE to avoid using quotes for entering what
>>>>             amounts to in-script data is abuse of the language
>>>>             justified by laziness... the amount of work you put
>>>>             yourself and anyone else who reads your code through is
>>>>             excessive relative to the benefit gained.
>>>>             >
>>>>             > NSE has its strengths... but as a method of creating
>>>>             data objects it sucks. Note that even the tidyverse
>>>>             (now) requires you to use quotes when you are not
>>>>             directly referring to something that already exists. And
>>>>             if you were... you might as well be creating a formula.
>>>>             >
>>>>             > On January 4, 2021 11:14:54 PM PST, Steven Yen
>>>>             <styen using ntu.edu.tw <mailto:styen using ntu.edu.tw>> wrote:
>>>>             >> I constantly define variable lists from a data frame
>>>>             (e.g., to define a
>>>>             >>
>>>>             >> regression equation). Line 3 below does just that.
>>>>             Placing each
>>>>             >> variable
>>>>             >> name in quotation marks is too much work especially
>>>>             for a long list so
>>>>             >> I
>>>>             >> do that with line 4. Is there an easier way to
>>>>             accomplish this----to
>>>>             >> define a list of variable names containing
>>>>             "a","c","e"? Thank you!
>>>>             >>
>>>>             >>> data<-as.data.frame(matrix(1:30,nrow=6))
>>>>             >>> colnames(data)<-c("a","b","c","d","e"); data
>>>>             >>    a  b  c  d  e
>>>>             >> 1 1  7 13 19 25
>>>>             >> 2 2  8 14 20 26
>>>>             >> 3 3  9 15 21 27
>>>>             >> 4 4 10 16 22 28
>>>>             >> 5 5 11 17 23 29
>>>>             >> 6 6 12 18 24 30
>>>>             >>> x1<-c("a","c","e"); x1 # line 3
>>>>             >> [1] "a" "c" "e"
>>>>             >>> x2<-colnames(subset(data,select=c(a,c,e))); x2 # line 4
>>>>             >> [1] "a" "c" "e"
>>>>             >>
>>>>             >> ______________________________________________
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>>>>             >> PLEASE do read the posting guide
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>>>>             <http://www.R-project.org/posting-guide.html>
>>>>             >> and provide commented, minimal, self-contained,
>>>>             reproducible code.
>>>>
>>>>             ______________________________________________
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>>>>             <http://www.R-project.org/posting-guide.html>
>>>>             and provide commented, minimal, self-contained,
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>>>>
>
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>
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