[R] Adding SORT to UNIQUE
Duncan Murdoch
murdoch@dunc@n @end|ng |rom gm@||@com
Wed Dec 22 18:12:57 CET 2021
On 22/12/2021 12:01 p.m., Stephen H. Dawson, DSL wrote:
> Data <- read.csv("./input/Source.csv", header=T)
> v1 <- sort(unique(Data[, 1]))
> cat(format(v1, justify = "right"), sep = "\n")
>
> OK, working with the options you presented. This is the combination
> where I gain the most benefit.
>
> However, there is no listing of a column header with the output of this
> syntax.
>
> > cat(format(v1, justify = "right"), sep = "\n")
> 2
> 3
> 4
> 5
> 6
> 7
> 8
> 9
> 10
> >
>
> NOTE
> The output here is correct (unique) based on the entries from the column.
>
> QUESTION
> How does one add a text label of something as simple as v1 to the
> vertical output of this syntax, please?
In this case, you'd just put in cat("v1\n") before the given command.
In the general case where you want to get the name of the column from
the dataframe, I think you'll need to write your own function. The one
Rui just posted looks pretty good. To get it to print without the row
numbers as in the example above, just change it a little in the header
and one other line:
print.sortUnique <- function(x, row.names = FALSE, ...){
n <- max(lengths(x))
y <- lapply(x, \(.x) c(.x, rep("", n - length(.x))))
y <- do.call(cbind.data.frame, y)
names(y) <- names(x)
print(y, row.names = row.names, ...)
invisible(x)
}
This will give
> Data2
V1 V2 V3 V4
3 2 2 1
5 4 3 2
6 5 4 4
7 6 5 5
8 9 6 6
9 11 8 9
12 15 9 10
14 16 11 11
15 17 14 12
18 18 15 13
19 19 17 14
20 19 16
20 18
19
with his example data.
Duncan Murdoch
>
> *Stephen Dawson, DSL*
> /Executive Strategy Consultant/
> Business & Technology
> +1 (865) 804-3454
> http://www.shdawson.com <http://www.shdawson.com>
>
>
> On 12/22/21 11:13 AM, Stephen H. Dawson, DSL via R-help wrote:
>> OK, now I get what you are suggesting.
>>
>> Much appreciated.
>>
>>
>> Kindest Regards,
>> *Stephen Dawson, DSL*
>> /Executive Strategy Consultant/
>> Business & Technology
>> +1 (865) 804-3454
>> http://www.shdawson.com <http://www.shdawson.com>
>>
>>
>> On 12/22/21 11:08 AM, Duncan Murdoch wrote:
>>> On 22/12/2021 10:55 a.m., Stephen H. Dawson, DSL wrote:
>>>> I see.
>>>>
>>>> So, we are talking taking the output into a new dataframe. I was hoping
>>>> to have the output rendered on screen without another dataframe, but I
>>>> can live with this option it if must occur.
>>>>
>>>> Am I correct the desired vertical output must first go to a dataframe?
>>>
>>> No, that's just one option. The other 3 don't use dataframes.
>>>
>>> Duncan Murdoch
>>>>
>>>>
>>>> *Stephen Dawson, DSL*
>>>> /Executive Strategy Consultant/
>>>> Business & Technology
>>>> +1 (865) 804-3454
>>>> http://www.shdawson.com <http://www.shdawson.com>
>>>>
>>>>
>>>> On 12/22/21 10:47 AM, Duncan Murdoch wrote:
>>>>> On 22/12/2021 10:20 a.m., Stephen H. Dawson, DSL wrote:
>>>>>> Thanks for the reply.
>>>>>>
>>>>>> Both syntax options work to render the correct (unique) output.
>>>>>> However,
>>>>>> the output is rendered as horizontal. What needs to happen to get the
>>>>>> output to render vertical, please?
>>>>>
>>>>> The result of those expressions is a vector of the same type as the
>>>>> column, so your question is really about how to get a vector to print
>>>>> one element per line.
>>>>>
>>>>> Probably the simplest way is to put the vector in a dataframe (or
>>>>> matrix, or tibble, depending on which formatting you prefer). For
>>>>> example,
>>>>>
>>>>>> v <- c("red", "green", "blue")
>>>>>> data.frame(v)
>>>>> v
>>>>> 1 red
>>>>> 2 green
>>>>> 3 blue
>>>>>
>>>>> If you want a more minimal display, try
>>>>>
>>>>>> cat(v, sep = "\n")
>>>>> red
>>>>> green
>>>>> blue
>>>>>
>>>>> or
>>>>>
>>>>>> cat(format(v, justify = "right"), sep = "\n")
>>>>> red
>>>>> green
>>>>> blue
>>>>>
>>>>> If you want this to happen when you auto-print the object, you can
>>>>> give it a class attribute and write a function to print that class,
>>>>> e.g.
>>>>>
>>>>>> class(v) <- "oneperline"
>>>>>>
>>>>>> print.oneperline <- function(x, ...) cat(format(x, justify =
>>>>> "right"), sep = "\n")
>>>>>>
>>>>>> v
>>>>> red
>>>>> green
>>>>> blue
>>>>>
>>>>> Duncan Murdoch
>>>>>
>>>>>>
>>>>>>
>>>>>> *Stephen Dawson, DSL*
>>>>>> /Executive Strategy Consultant/
>>>>>> Business & Technology
>>>>>> +1 (865) 804-3454
>>>>>> http://www.shdawson.com <http://www.shdawson.com>
>>>>>>
>>>>>>
>>>>>> On 12/21/21 11:38 AM, Duncan Murdoch wrote:
>>>>>>> On 21/12/2021 11:31 a.m., Duncan Murdoch wrote:
>>>>>>>> On 21/12/2021 11:20 a.m., Stephen H. Dawson, DSL wrote:
>>>>>>>>> Thanks for the reply.
>>>>>>>>>
>>>>>>>>> sort(unique(Data[1]))
>>>>>>>>> Error in `[.data.frame`(x, order(x, na.last = na.last,
>>>>>>>>> decreasing =
>>>>>>>>> decreasing)) :
>>>>>>>>> undefined columns selected
>>>>>>>>
>>>>>>>> That's the wrong syntax: Data[1] is not "column one of Data". Use
>>>>>>>> Data[[1]] for that, so
>>>>>>>>
>>>>>>>> sort(unique(Data[[1]]))
>>>>>>>
>>>>>>> Actually, I'd probably recommend
>>>>>>>
>>>>>>> sort(unique(Data[, 1]))
>>>>>>>
>>>>>>> instead. This treats Data as a matrix rather than as a list.
>>>>>>> Dataframes are lists that look like matrices, but to me the matrix
>>>>>>> aspect is usually more intuitive.
>>>>>>>
>>>>>>> Duncan Murdoch
>>>>>>>
>>>>>>>>
>>>>>>>> I think Rui already pointed out the typo in the quoted text
>>>>>>>> below...
>>>>>>>>
>>>>>>>> Duncan Murdoch
>>>>>>>>
>>>>>>>>>
>>>>>>>>> The recommended syntax did not work, as listed above.
>>>>>>>>>
>>>>>>>>> What I want is the sort of distinct column output. Again, the
>>>>>>>>> column
>>>>>>>>> may
>>>>>>>>> be text or numbers. This is a huge analysis effort with data
>>>>>>>>> coming at
>>>>>>>>> me from many different sources.
>>>>>>>>>
>>>>>>>>>
>>>>>>>>> *Stephen Dawson, DSL*
>>>>>>>>> /Executive Strategy Consultant/
>>>>>>>>> Business & Technology
>>>>>>>>> +1 (865) 804-3454
>>>>>>>>> http://www.shdawson.com <http://www.shdawson.com>
>>>>>>>>>
>>>>>>>>>
>>>>>>>>> On 12/21/21 11:07 AM, Duncan Murdoch wrote:
>>>>>>>>>> On 21/12/2021 10:16 a.m., Stephen H. Dawson, DSL via R-help
>>>>>>>>>> wrote:
>>>>>>>>>>> Thanks everyone for the replies.
>>>>>>>>>>>
>>>>>>>>>>> It is clear one either needs to write a function or put the
>>>>>>>>>>> unique
>>>>>>>>>>> entries into another dataframe.
>>>>>>>>>>>
>>>>>>>>>>> It seems odd R cannot sort a list of unique column entries with
>>>>>>>>>>> ease.
>>>>>>>>>>> Python and SQL can do it with ease.
>>>>>>>>>>
>>>>>>>>>> I've seen several responses that looked pretty simple. It's
>>>>>>>>>> hard to
>>>>>>>>>> beat sort(unique(x)), though there's a fair bit of confusion
>>>>>>>>>> about
>>>>>>>>>> what you actually want. Maybe you should post an example of the
>>>>>>>>>> code
>>>>>>>>>> you'd use in Python?
>>>>>>>>>>
>>>>>>>>>> Duncan Murdoch
>>>>>>>>>>
>>>>>>>>>>>
>>>>>>>>>>> QUESTION
>>>>>>>>>>> Is there a simpler means than other than the unique function to
>>>>>>>>>>> capture
>>>>>>>>>>> distinct column entries, then sort that list?
>>>>>>>>>>>
>>>>>>>>>>>
>>>>>>>>>>> *Stephen Dawson, DSL*
>>>>>>>>>>> /Executive Strategy Consultant/
>>>>>>>>>>> Business & Technology
>>>>>>>>>>> +1 (865) 804-3454
>>>>>>>>>>> http://www.shdawson.com <http://www.shdawson.com>
>>>>>>>>>>>
>>>>>>>>>>>
>>>>>>>>>>> On 12/20/21 5:53 PM, Rui Barradas wrote:
>>>>>>>>>>>> Hello,
>>>>>>>>>>>>
>>>>>>>>>>>> Inline.
>>>>>>>>>>>>
>>>>>>>>>>>> Às 21:18 de 20/12/21, Stephen H. Dawson, DSL via R-help
>>>>>>>>>>>> escreveu:
>>>>>>>>>>>>> Thanks.
>>>>>>>>>>>>>
>>>>>>>>>>>>> sort(unique(Data[[1]]))
>>>>>>>>>>>>>
>>>>>>>>>>>>> This syntax provides row numbers, not column values.
>>>>>>>>>>>>
>>>>>>>>>>>> This is not right.
>>>>>>>>>>>> The syntax Data[1] extracts a sub-data.frame, the syntax
>>>>>>>>>>>> Data[[1]]
>>>>>>>>>>>> extracts the column vector.
>>>>>>>>>>>>
>>>>>>>>>>>> As for my previous answer, it was not addressing the
>>>>>>>>>>>> question, I
>>>>>>>>>>>> misinterpreted it as being a question on how to sort by numeric
>>>>>>>>>>>> order
>>>>>>>>>>>> when the data is not numeric. Here is a, hopefully, complete
>>>>>>>>>>>> answer.
>>>>>>>>>>>> Still with package stringr.
>>>>>>>>>>>>
>>>>>>>>>>>>
>>>>>>>>>>>> cols_to_sort <- 1:4
>>>>>>>>>>>>
>>>>>>>>>>>> Data2 <- lapply(Data[cols_to_sort], \(x){
>>>>>>>>>>>> stringr::str_sort(unique(x), numeric = TRUE)
>>>>>>>>>>>> })
>>>>>>>>>>>>
>>>>>>>>>>>>
>>>>>>>>>>>> Or using Avi's suggestion of writing a function to do all the
>>>>>>>>>>>> work and
>>>>>>>>>>>> simplify the lapply loop later,
>>>>>>>>>>>>
>>>>>>>>>>>>
>>>>>>>>>>>> unisort2 <- function(vec, ...)
>>>>>>>>>>>> stringr::str_sort(unique(vec), ...)
>>>>>>>>>>>> Data2 <- lapply(Data[cols_to_sort], unisort, numeric = TRUE)
>>>>>>>>>>>>
>>>>>>>>>>>>
>>>>>>>>>>>> Hope this helps,
>>>>>>>>>>>>
>>>>>>>>>>>> Rui Barradas
>>>>>>>>>>>>
>>>>>>>>>>>>
>>>>>>>>>>>>>
>>>>>>>>>>>>> *Stephen Dawson, DSL*
>>>>>>>>>>>>> /Executive Strategy Consultant/
>>>>>>>>>>>>> Business & Technology
>>>>>>>>>>>>> +1 (865) 804-3454
>>>>>>>>>>>>> http://www.shdawson.com <http://www.shdawson.com>
>>>>>>>>>>>>>
>>>>>>>>>>>>>
>>>>>>>>>>>>> On 12/20/21 11:58 AM, Stephen H. Dawson, DSL via R-help wrote:
>>>>>>>>>>>>>> Hi,
>>>>>>>>>>>>>>
>>>>>>>>>>>>>>
>>>>>>>>>>>>>> Running a simple syntax set to review entries in dataframe
>>>>>>>>>>>>>> columns.
>>>>>>>>>>>>>> Here is the working code.
>>>>>>>>>>>>>>
>>>>>>>>>>>>>> Data <- read.csv("./input/Source.csv", header=T)
>>>>>>>>>>>>>> describe(Data)
>>>>>>>>>>>>>> summary(Data)
>>>>>>>>>>>>>> unique(Data[1])
>>>>>>>>>>>>>> unique(Data[2])
>>>>>>>>>>>>>> unique(Data[3])
>>>>>>>>>>>>>> unique(Data[4])
>>>>>>>>>>>>>>
>>>>>>>>>>>>>> I would like to add sort the unique entries. The data in the
>>>>>>>>>>>>>> various
>>>>>>>>>>>>>> columns are not defined as numbers, but also text. I realize
>>>>>>>>>>>>>> 1 and
>>>>>>>>>>>>>> 10 will not sort properly, as the column is not defined as a
>>>>>>>>>>>>>> number,
>>>>>>>>>>>>>> but want to see what I have in the columns viewed as sorted.
>>>>>>>>>>>>>>
>>>>>>>>>>>>>> QUESTION
>>>>>>>>>>>>>> What is the best process to sort unique output, please?
>>>>>>>>>>>>>>
>>>>>>>>>>>>>>
>>>>>>>>>>>>>> Thanks.
>>>>>>>>>>>>>
>>>>>>>>>>>>> ______________________________________________
>>>>>>>>>>>>> R-help using r-project.org mailing list -- To UNSUBSCRIBE and
>>>>>>>>>>>>> more, see
>>>>>>>>>>>>> https://stat.ethz.ch/mailman/listinfo/r-help
>>>>>>>>>>>>> PLEASE do read the posting guide
>>>>>>>>>>>>> http://www.R-project.org/posting-guide.html
>>>>>>>>>>>>> and provide commented, minimal, self-contained, reproducible
>>>>>>>>>>>>> code.
>>>>>>>>>>>>
>>>>>>>>>>>
>>>>>>>>>>> ______________________________________________
>>>>>>>>>>> R-help using r-project.org mailing list -- To UNSUBSCRIBE and more,
>>>>>>>>>>> see
>>>>>>>>>>> https://stat.ethz.ch/mailman/listinfo/r-help
>>>>>>>>>>> PLEASE do read the posting guide
>>>>>>>>>>> http://www.R-project.org/posting-guide.html
>>>>>>>>>>> and provide commented, minimal, self-contained, reproducible
>>>>>>>>>>> code.
>>>>>>>>>>
>>>>>>>>>>
>>>>>>>>>
>>>>>>>>>
>>>>>>>>
>>>>>>>
>>>>>>>
>>>>>>
>>>>>
>>>>>
>>>>
>>>
>>>
>>
>> ______________________________________________
>> R-help using r-project.org mailing list -- To UNSUBSCRIBE and more, see
>> https://stat.ethz.ch/mailman/listinfo/r-help
>> PLEASE do read the posting guide
>> http://www.R-project.org/posting-guide.html
>> and provide commented, minimal, self-contained, reproducible code.
>>
>
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