[R] Calculation of Age heaping
Jim Lemon
drj|m|emon @end|ng |rom gm@||@com
Mon Aug 9 14:17:17 CEST 2021
And if you really don't like programming:
whipple_index<-function(x,td=c(0,5)) {
wi<-rep(NA,11)
names(wi)<-c(paste0("wi",0:9),"O/all")
for(i in 0:9) {
ttd<-which((x %% 10) %in% i)
wi[i+1]<-length(ttd) * 100/length(x)
}
ttd<-which((x %% 10) %in% td)
wi[11]<-length(ttd) * 100/(length(x)/length(td))
return(wi)
}
I haven't tested this extensively, but it may be helpful. You can
specify the final digits for the overall test. Select your ages before
passing them to whipple_index.
Jim
On Mon, Aug 9, 2021 at 9:05 PM Greg Minshall <minshall using umich.edu> wrote:
>
> Md,
>
> if this is what you are looking for:
> ----
> https://en.wikipedia.org/wiki/Whipple%27s_index
> ----
>
> then, the article says the algorithm is
> ----
> The index score is obtained by summing the number of persons in the age
> range 23 and 62 inclusive, who report ages ending in 0 and 5, dividing
> that sum by the total population between ages 23 and 62 years inclusive,
> and multiplying the result by 5. Restated as a percentage, index scores
> range between 100 (no preference for ages ending in 0 and 5) and 500
> (all people reporting ages ending in 0 and 5).
> ----
>
> that seems fairly straight forward. if you are trying to learn R,
> and/or learn programming, i might suggest you *not* use a package, and
> rather work on coding up the calculation yourself. that would probably
> be a good, but not too hard, exercise, of some interest. enjoy!
>
> cheers, Greg
>
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