[R] substitute column data frame based on name stored in variable in r

[Luigi Marongiu]

Thank you very much, but that would make even more work due to the
duplication...

On Mon, Aug 9, 2021 at 10:53 AM Jim Lemon <drjimlemon using gmail.com> wrote:
>
> Hi Luigi,
> It looks to me as though you will have to copy the data frame or store
> the output in a new data frame.
>
> Jim
>
> On Mon, Aug 9, 2021 at 6:26 PM Luigi Marongiu <marongiu.luigi using gmail.com> wrote:
> >
> > Hello,
> > I would like to recursively select the columns of a dataframe by
> > strong the names of the dataframe in a vector and extracting one
> > element of the vector at a time. This I can do with, for instance:
> > ```
> > vect = names(df)
> > sub_df[vect[1]]
> > ```
> >
> > The problem is that I would like also to change the values of the
> > selected column using some logic as in `df$column[df$column == value]
> > <- new.value`, but I am confused on the syntax for the vectorized
> > version. Specifically, this does not work:
> > ```
> > sub_df[vect[1] == 0] = "No"
> > ```
> > What would be the correct approach?
> > Thank you
> >
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-- 
Best regards,
Luigi