[R] (i want change G3 and G2 to variable tke all elements in rows) (truth[(truth[, 1]=="G3" & truth[, 2]=="G2") | (truth[, 1]=="G2" & truth[, 2]=="G3"), 3]<-1
PIKAL Petr
petr@p|k@| @end|ng |rom prechez@@cz
Mon Sep 7 08:43:37 CEST 2020
Hi
You still fail to send your message in plain text, so it is unreadable.
If I managed to decipher it correctly what you wanted you probably could set 2
related logical expression and considering that FALSE is 0 and TRUE is 1 you
get desired result.
Cheers
Petr
> -----Original Message-----
> From: R-help <r-help-bounces using r-project.org> On Behalf Of Hesham A. AL-
> bukhaiti via R-help
> Sent: Monday, September 7, 2020 5:49 AM
> To: r-help using r-project.org
> Subject: [R] (i want change G3 and G2 to variable tke all elements in rows)
> (truth[(truth[, 1]=="G3" & truth[, 2]=="G2") | (truth[, 1]=="G2" & truth[,
> 2]=="G3"), 3]<-1
>
> helloout<-read.csv("outbr.csv")truth<-out[,seq(1,2)]for example :
> If row1= G1 and row2=G2 , and row 1 = G2 and row 2= G1,make G3=1 # note
> G1 and G2 are values from 1 to 2000 #if this happend add to thrid column in
> truth 1 otherwise add 0 as in statment follow
> truth<-
> cbind(as.character(truth[,1]),as.character(truth[,2])
> ,as.data.frame(rep(
> 0,,dim(out)[1])));#here just G2 and G3, i want make loop to cam[are all
> values
> from G1 to G2000 truth[(truth[,1]=="G3" & truth[,2]=="G2") |
> (truth[,1]=="G2"
> & truth[,2]=="G3"),3]<-1 ###############################3(Simply they
> regulate the other. If element A is in the first group , and it is related
> to
> element B in the second group , and element B also in in the first group ,
> and
> it is related to element A(the same element in the first group) in the
> second
> group , we write 1 and otherwise 0.
> this the distination result:
> I want this result
> G1 G2 G3 D B 1 B D 1 A D 0 B A 1B C 0A B
> 1
>
> [[alternative HTML version deleted]]
>
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