[R] all.equal and use.names

[John Harrold]

Is there a way to compare t1 and t2 above such that the name is used
instead of the index?

On Wed, May 27, 2020 at 9:14 PM Bert Gunter <bgunter.4567 using gmail.com> wrote:

> Nope. You misread I think. It says that use.names = TRUE causes mismatches
> to be **reported** by name rather than index, not that it is recursing by
> name. It still recurses by component indices.
>
> However, I still think that is wrong. It is not reporting mismatches
> **by** name -- it is reporting mismatches **in** names as well as in value.
>
>
> Bert Gunter
>
> "The trouble with having an open mind is that people keep coming along and
> sticking things into it."
> -- Opus (aka Berkeley Breathed in his "Bloom County" comic strip )
>
>
> On Wed, May 27, 2020 at 8:23 PM John Harrold <john.m.harrold using gmail.com>
> wrote:
>
>> Howdy Folks,
>>
>> I believe I'm having trouble understanding the documentation for
>> all.equal.
>> If I have two lists like this:
>>
>> t1 = list(a = c(1,2,3),
>>           b = c("1", "2", "3"))
>> t2 = list( b = c("1", "2", "3"),
>>            a = c(1,2,3))
>>
>> If I read the documentation correctly, by setting use.names equal to TRUE
>> I
>> believe this comparison should evaluate as true:
>>
>> all.equal(t1,t2, use.names=TRUE)
>>
>> However, I get the following output:
>>
>> which appears as though it is performing the comparison based on walking
>> through indices and comparing that way.
>>
>> [1] "Names: 2 string mismatches"
>> [2] "Component 1: Modes: numeric, character"
>> [3] "Component 1: target is numeric, current is character"
>> [4] "Component 2: Modes: character, numeric"
>> [5] "Component 2: target is character, current is numeric"
>>
>> Can someone tell me what I'm doing wrong here?
>> --
>> John
>> :wq
>>
>>         [[alternative HTML version deleted]]
>>
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>>
>

-- 
John
:wq

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