[R] Yearly hourly mean and NA: SOLVED

Jeff Newmiller jdnewm|| @end|ng |rom dcn@d@v|@@c@@u@
Thu Jun 4 08:37:51 CEST 2020


Glad you had a positive experience with the documentation... there are many gems to be found there.

But I don't think rm.na will work... the na comes before the rm for some reason.

On June 3, 2020 11:13:28 PM PDT, Ogbos Okike <giftedlife2014 using gmail.com> wrote:
>Dear Jeff,
>It worked!!! I took a second look at "?mean" as you suggested.
>I then adjusted my code, inserting rm.na here and there until it was
>fine.
>Thank you very much.
>Warm regards.
>Ogbos
>On Thu, Jun 4, 2020 at 3:14 AM Jeff Newmiller
><jdnewmil using dcn.davis.ca.us>
>wrote:
>
>> Perhaps read ?mean...
>>
>> On June 3, 2020 6:15:11 PM PDT, Ogbos Okike
><giftedlife2014 using gmail.com>
>> wrote:
>> >Dear Jeff,
>> >Thank you so much for your time.
>> >I tried your code. It successfully assigned NA to the zeros.
>> >
>> >But the main code seems not to work with the NAs. The mean, for
>> >example,
>> >resulted in NA. I am attaching the data for a period of one year 
>and
>> >the
>> >code which I use  in plotting the data. Maybe it might be easier for
>> >you to
>> >spot where I run into error (my plot was just empty).
>> >Thanks again.
>> >Best regards
>> >Ogbos
>> >
>> >
>> >On Wed, Jun 3, 2020 at 8:47 PM Jeff Newmiller
>> ><jdnewmil using dcn.davis.ca.us>
>> >wrote:
>> >
>> >> df[[ 5 ]][ 0 == df[[ 5 ]] ] <- NA
>> >>
>> >> On June 3, 2020 1:59:06 AM PDT, Ogbos Okike
>> ><giftedlife2014 using gmail.com>
>> >> wrote:
>> >> >Dear R-Experts,
>> >> >I have a cosmic ray data that span several years. The data frame
>is
>> >of
>> >> >the
>> >> >form:
>> >> >03 01 01 00    3809
>> >> >03 01 01 01    3771
>> >> >03 01 01 02    3743
>> >> >03 01 01 03    3747
>> >> >03 01 01 04    3737
>> >> >03 01 01 05    3751
>> >> >03 01 01 06    3733
>> >> >03 01 01 07    3732.
>> >> >where the columns 1 to 5 stand for year, month, day, hour and
>> >counts.
>> >> >Some hours when the station does not have data are assigned zero,
>> >> >implying
>> >> >there could be several zeros in column 5. Since my aim is to plot
>> >the
>> >> >hourly mean for all the  years, I started learning with one year
>-
>> >year
>> >> >2003.
>> >> >
>> >> >I carefully went through the data, removing any day that contains
>> >zero
>> >> >for
>> >> >any of the hours.  Instead of the 365 days in the year 2003, I
>ended
>> >up
>> >> >with 362 days.
>> >> >
>> >> >I saved that as CLMX1C (now stored in Ogbos2 with dput function,
>see
>> >> >attached please).
>> >> >
>> >> >If I run the data with my script, it gives me what I am
>expecting.
>> >My
>> >> >script is:
>> >> >d<-read.table("CLMX1C",col.names=c("h","count"))
>> >> >y<-d$count
>> >> >data<-(y-mean(y))/mean(y)*100
>> >> >
>> >> >A<-matrix(rep(1:24,362))
>> >> >B<-matrix(data)
>> >> >
>> >> > oodf<-data.frame(A,B)
>> >> > oodf<-data.frame(A,B)
>> >> >library(plotrix)
>> >> >std.error<-function(x) return(sd(x)/(sum(!is.na(x))))
>> >> >oomean<-as.vector(by(oodf$B,oodf$A,mean))
>> >> >oose<-as.vector(by(oodf$B,oodf$A,std.error))
>> >> >plot(1:24,oomean,type="b",ylim=c(-0.4,0.5),
>> >> > xlab="Hours",ylab="CR count",main="CR daily variation for 2004")
>> >> >dispersion(1:24,oomean,oose,arrow.cap=.01)
>> >> >
>> >> >Now, instead of foraging through the big data removing the day
>for
>> >> >which
>> >> >there is a missing data for any hour, I wish to try to replace
>the
>> >> >missing
>> >> >data with NA and hoping that it will do the job for me.
>> >> >
>> >> >I added just three lines in the script above:
>> >> >d<-read.table("2003",col.names=c("y","m","d","h","count"))
>> >> >y<-d$count
>> >> >df<-data.frame(y)#line 1
>> >> >library('dplyr') # line 2
>> >> >y<-na_if(df, 0) #line 3
>> >> >data<-(y-mean(y))/mean(y)*100.
>> >> >Then I started getting error messages:
>> >> >Error in is.data.frame(x) :
>> >> >  (list) object cannot be coerced to type 'double'
>> >> >In addition: There were 26 warnings (use warnings() to see them).
>> >> >
>> >> >I hope you will assist me to deal with the issues of replacing
>zeros
>> >> >with
>> >> >NA in column 5 in such a way that my code will run.
>> >> >
>> >> >Iam ever indebted!!
>> >> >Best regards
>> >> >Ogbos
>> >> >______________________________________________
>> >> >R-help using r-project.org mailing list -- To UNSUBSCRIBE and more, see
>> >> >https://stat.ethz.ch/mailman/listinfo/r-help
>> >> >PLEASE do read the posting guide
>> >> >http://www.R-project.org/posting-guide.html
>> >> >and provide commented, minimal, self-contained, reproducible
>code.
>> >>
>> >> --
>> >> Sent from my phone. Please excuse my brevity.
>> >>
>>
>> --
>> Sent from my phone. Please excuse my brevity.
>>

-- 
Sent from my phone. Please excuse my brevity.



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