[R] R Subset by Factor levels

[Engin Yılmaz]

I solve this as follows

m2 <- subset(m1,`Classification Description`=="Borrowing from the Public" |
`Classification Description`=="By Other Means"  | `Classification
Description`=="Total Surplus (+) or Deficit (-)")

sincerely
Engin YILMAZ

Engin Yılmaz <ispanyolcom using gmail.com>, 29 Tem 2020 Çar, 16:57 tarihinde şunu
yazdı:

> Dear
>
> I try to create a new subset from my dataframe.
> My dataframe's name is m1.
> "Classification Description" column has 15 different factors.
> The following code is used creating a subset for 1 factor.
> m2<-m1[m1$`Classification Description` == levels(m1$`Classification
> Description`)[1],]
>
> My aim is to create a subset with 4 different factors. For example,
> levels(m1$`Classification Description`)[1]
> levels(m1$`Classification Description`)[15]
> levels(m1$`Classification Description`)[2]
> levels(m1$`Classification Description`)[4]
>
> I try to following code but it didnt work
>
> m2<-m1[m1$`Classification Description` == levels(m1$`Classification
> Description`)[c(1,15,2,4],]
>
> How can I solve This Problem ?
>
> Example from my dataframe
>
> `Record Date` `Classification Description`             `Current Month
> Budget Amount`
>    <date>        <fct>
>         <dbl>
>  1 2019-06-30    Total On-Budget and Off-Budget Results:
>           NA
>  2 2019-06-30    Off-Budget Surplus (+) or Deficit (-)
>  41998597035.
>  3 2019-06-30    Total Outlays
> 342428650968.
>  4 2019-06-30    By Other Means
> 51648504883.
>  5 2019-06-30    On-Budget Outlays
> 292169836521.
>  6 2019-06-30    Off-Budget Outlays
> 50258814447.
>  7 2019-06-30    Total Receipts
>  333952332514.
>  8 2019-06-30    On-Budget Surplus (+) or Deficit (-)
>  -50474915489.
>  9 2019-06-30    Off-Budget Receipts
>  92257411482
> 10 2019-06-30    Total On-Budget and Off-Budget Financing
>  8476318454
>
>
>
> --
> *Saygılarımla*
> Engin YILMAZ
>


-- 
*Saygılarımla*
Engin YILMAZ

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