[R] R Subset by Factor levels

[Rui Barradas]

Hello,

Try %in% instead of == in:

m2<-m1[m1$`Classification Description` == levels(m1$`Classification Description`)[c(1,15,2,4],]


Hope this helps,

Rui Barradas



Às 14:57 de 29/07/2020, Engin Yılmaz escreveu:
> Dear
>
> I try to create a new subset from my dataframe.
> My dataframe's name is m1.
> "Classification Description" column has 15 different factors.
> The following code is used creating a subset for 1 factor.
> m2<-m1[m1$`Classification Description` == levels(m1$`Classification
> Description`)[1],]
>
> My aim is to create a subset with 4 different factors. For example,
> levels(m1$`Classification Description`)[1]
> levels(m1$`Classification Description`)[15]
> levels(m1$`Classification Description`)[2]
> levels(m1$`Classification Description`)[4]
>
> I try to following code but it didnt work
>
> m2<-m1[m1$`Classification Description` == levels(m1$`Classification
> Description`)[c(1,15,2,4],]
>
> How can I solve This Problem ?
>
> Example from my dataframe
>
> `Record Date` `Classification Description`             `Current Month
> Budget Amount`
>     <date>        <fct>
>        <dbl>
>   1 2019-06-30    Total On-Budget and Off-Budget Results:
>          NA
>   2 2019-06-30    Off-Budget Surplus (+) or Deficit (-)
>   41998597035.
>   3 2019-06-30    Total Outlays
> 342428650968.
>   4 2019-06-30    By Other Means
> 51648504883.
>   5 2019-06-30    On-Budget Outlays
> 292169836521.
>   6 2019-06-30    Off-Budget Outlays
> 50258814447.
>   7 2019-06-30    Total Receipts
>   333952332514.
>   8 2019-06-30    On-Budget Surplus (+) or Deficit (-)
>   -50474915489.
>   9 2019-06-30    Off-Budget Receipts
>   92257411482
> 10 2019-06-30    Total On-Budget and Off-Budget Financing
>   8476318454
>
>
>


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