[R] Removing a space from a string

[Kimmo Elo]

Hi!

How about this?

--- snip ---

> x <- c("STRING 01.  Remainder of the string","STR ING 01.  Remainder
of the string","STRIN G 01.  Remainder of the string","STR  IN G
01.  Remainder of the string")

> x1<-unlist(strsplit(x,"\\."))

> for (i in seq(1,length(x1),2)) { x[(i+1) %/% 2]<-paste(gsub("
","",x1[i]),x1[i+1],sep=".") }

> x
[1] "STRING01.  Remainder of the string" "STRING01.  Remainder of the
string" "STRING01.  Remainder of the string"
[4] "STRING01.  Remainder of the string"

--- snip ---

Or do I miss something?

Best,

Kimmo


ti, 2020-07-28 kello 17:19 -0700, Dennis Fisher kirjoitti:
> Richard
> 
> In reply to your “first response”, the text was originally in a Word
> document and it did NOT contain the errant spaces.  I used read_docx
> in the textreadr package to access the text.  The spaces were added
> during that step.  I am copying the maintainer of that package to see
> if he has any idea as to the source.
> 
> Thanks for your regular expression suggestion.
> 
> Dennis
> 
> 
> Dennis Fisher MD
> P < (The "P Less Than" Company)
> Phone / Fax: 1-866-PLessThan (1-866-753-7784)
> www.PLessThan.com <http://www.plessthan.com/>
> 
> 
> 
> 
> > On Jul 28, 2020, at 5:11 PM, Richard O'Keefe <raoknz using gmail.com>
> > wrote:
> > 
> > The first response has to be "how did the spaces get there
> > in the first place?"  Can you fix the process that creates
> > the data?  If the process sometimes generates one extra
> > space, are you sure it never generates two?
> > 
> > But let's treat this purely as a regular expression
> > problem, where if there is a space before a dot you want
> > to delete the first.  In vi(1) you would do
> > 
> > s/^\([^  .]*\) \([^.]*\)/\1\2/
> > 
> > but apparently there is *supposed* to be a space before
> > the 01, so it is only when there are two or more spaces
> > that one should be deleted, so we'd want
> > 
> > s/^\([^  .]*\) \([^ .]* \)/\1\2/
> > 
> > I leave converting that to R as an exercise for the reader.
> > 
> > 
> > 
> > 
> > On Wed, 29 Jul 2020 at 08:20, Dennis Fisher <fisher using plessthan.com
> > <mailto:fisher using plessthan.com>> wrote:
> > R 4.0.2
> > OS X
> > 
> > Colleagues
> > 
> > I have strings that contain a space in an unexpected location.  The
> > intended string is:
> >         “STRING 01.  Remainder of the string"
> > However, variants are:
> >         “STR ING 01.  Remainder of the string"
> >         “STRIN G 01.  Remainder of the string"
> > 
> > I would like a general approach to deleting a space, but only if it
> > appears before the period.  Any suggestions on a regular expression
> > for this?
> > 
> > Dennis
> > 
> > Dennis Fisher MD
> > P < (The "P Less Than" Company)
> > Phone / Fax: 1-866-PLessThan (1-866-753-7784)
> > www.PLessThan.com <http://www.plessthan.com/> <
> > http://www.plessthan.com/ <http://www.plessthan.com/>>
> > 
> > 
> > 
> > 
> > 
> >         [[alternative HTML version deleted]]
> > 
> > ______________________________________________
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> 
> 	[[alternative HTML version deleted]]
> 
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