[R] Substitution in expressions

[Bert Gunter]

Perhaps something like this (apologies if beating a dead horse):

plot(NA,NA, xlim = c(-1,5),ylim = c(-1,5), xlab = "", ylab = "")
for(i in 1:3)  text(i,i,labels =bquote(2^.(i)))

Cheers,
Bert

Bert Gunter

"The trouble with having an open mind is that people keep coming along and
sticking things into it."
-- Opus (aka Berkeley Breathed in his "Bloom County" comic strip )


On Tue, Mar 26, 2019 at 8:27 AM Viechtbauer, Wolfgang (SP) <
wolfgang.viechtbauer using maastrichtuniversity.nl> wrote:

> Hi Bert,
>
> I am indeed creating a mathematical expression, but ?plotmath doesn't
> cover how to do such a vectorized substitution.
>
> Best,
> Wolfgang
>
> -----Original Message-----
> From: Bert Gunter [mailto:bgunter.4567 using gmail.com]
> Sent: Tuesday, 26 March, 2019 15:52
> To: Viechtbauer, Wolfgang (SP)
> Cc: r-help mailing list
> Subject: Re: [R] Substitution in expressions
>
> I believe you're going about this the wrong way. You seem to want
> mathematical expressions. Fot this, see ?plotmath.
>
> Cheers,
> Bert
>
> Bert Gunter
>
> "The trouble with having an open mind is that people keep coming along and
> sticking things into it."
> -- Opus (aka Berkeley Breathed in his "Bloom County" comic strip )
>
> On Tue, Mar 26, 2019 at 6:28 AM Viechtbauer, Wolfgang (SP) <
> wolfgang.viechtbauer using maastrichtuniversity.nl> wrote:
> Hi All,
>
> I am trying to create a vector of expressions, where the elements in the
> expressions are contained in other vectors (i.e., they should be
> substituted). I made some attempts with substitute() and bquote(), but
> couldn't get this to work. My solution so far is:
>
> base <- 1:5
> expo <- c(2,2,3,3,4)
> exvec <- as.expression(unname(mapply(function(x,y) bquote(.(x)^.(y)),
> base, expo)))
>
> plot(NA, NA, xlim=c(0,6), ylim=c(0,2))
> text(1:5, 1, exvec)
>
> Any ideas how I could get this to work with substitute() and/or bquote()?
>
> Best,
> Wolfgang
>

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