[R] Substitution in expressions

Bert Gunter bgunter@4567 @end|ng |rom gm@||@com
Tue Mar 26 15:51:46 CET 2019


I believe you're going about this the wrong way. You seem to want
mathematical expressions. Fot this, see ?plotmath.

Cheers,
Bert

Bert Gunter

"The trouble with having an open mind is that people keep coming along and
sticking things into it."
-- Opus (aka Berkeley Breathed in his "Bloom County" comic strip )


On Tue, Mar 26, 2019 at 6:28 AM Viechtbauer, Wolfgang (SP) <
wolfgang.viechtbauer using maastrichtuniversity.nl> wrote:

> Hi All,
>
> I am trying to create a vector of expressions, where the elements in the
> expressions are contained in other vectors (i.e., they should be
> substituted). I made some attempts with substitute() and bquote(), but
> couldn't get this to work. My solution so far is:
>
> base <- 1:5
> expo <- c(2,2,3,3,4)
> exvec <- as.expression(unname(mapply(function(x,y) bquote(.(x)^.(y)),
> base, expo)))
>
> plot(NA, NA, xlim=c(0,6), ylim=c(0,2))
> text(1:5, 1, exvec)
>
> Any ideas how I could get this to work with substitute() and/or bquote()?
>
> Best,
> Wolfgang
>
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