[R] Help with a third ggplot error

Sam Charya @@mch@ry@ @end|ng |rom y@hoo@com@@u
Tue Jun 18 05:50:27 CEST 2019

 Thanks a lot Boris, I tried out your worked out solution and it works just perfectly fine. No doubt I need a lot of practice with regexr and the pattern stated by you - I will do that now. Thanks a lot for pointing me in the right direction. Appreciate it a lot.

    On Monday, 17 June 2019, 2:39:14 pm GMT+5:30, Boris Steipe <boris.steipe using utoronto.ca> wrote:  
 (Technically you are now thread-hijacking. But here goes:)

mydf <- data.frame(V11 = c("DD Pack0.002",
                          "FTA English News0.003",
                          "FTA Complimentary0.004"),
                  stringsAsFactors = FALSE)

# regex matching start-of-string(letters or blanks)(numbers, a decimal
# point, more numbers)end-of-string: "^([a-zA-Z ]+)([0-9]+\\.[0-9]+)$"

# first check that all elements are matched by the regex. If not, an assumption
# of how the strings are patterned is not true ... 
all(grepl("^([a-zA-Z ]+)([0-9]+\\.[0-9]+)$", V11))  # must be true!

mydf$`Channel name` <- gsub("^([a-zA-Z ]+)([0-9]+\\.[0-9]+)$", "\\1", mydf$V11)
mydf$Price          <- gsub("^([a-zA-Z ]+)([0-9]+\\.[0-9]+)$", "\\2", mydf$V11)

#                      V11      Channel name Price
# 1          DD Pack0.002          DD Pack 0.002
# 2  FTA English News0.003  FTA English News 0.003
# 3 FTA Complimentary0.004 FTA Complimentary 0.004

Note this _will_ give wrong results if channel names like "ABC4" exist.


> On 2019-06-15, at 15:40, Sam Charya via R-help <r-help using r-project.org> wrote:
> Hello All,
> I need help with splitting a string. My data frame is in the following format:
>                      V11            DD Pack0.002  FTA English News0.003  FTA Complimentary0.004                WB1.185              WION1.186        Al Jazeera0.007      Animal Planet2.368    Asianet Movies17.709      Calcutta News0.0010    Comedy Central5.90
> I read the file from a csv and set header = False, hence it is named V1. 
> The data consists of names of Channels and their prices. For example: Row 1: Name of the Channel is 'DD Pack' and the Price is 0.00.similarly for Row 5, the name of the Channel is 'WION' and the price is 1.18.
> similarly for Row 8: The name of the Channel is 'Asianet Movies' and the price is 17.70. 
> My question is: How would I separate the data into 2 columns: One for the Channel name and one for the Price. 
> For example. The Heading should be for Col1: 'Channel Name' and for Col2: 'Price'The data under  'Channel Name' should be 'DD Pack' and for 'Price' should be 0.00 and so on and so forth. 
> The letters and the numeric appears together so there is no separator and I am not being able to figure this out. Kindly please help resolve this. 
> Many Thanks in advance for your help. This is my first  question ever to the community so apologies if I have made a mistake in sending it to the wrong group - kindly direct if that is the case. 
> sam. 
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