[R] reduce and intersect question (maybe)?

[Andras Farkas]

Works well! Thanks!
Andras  

    On Thursday, February 21, 2019, 8:47:51 AM EST, Jeff Newmiller <jdnewmil using dcn.davis.ca.us> wrote:  
 
 Use ?merge instead of intersect.

On February 21, 2019 5:22:46 AM PST, Andras Farkas via R-help <r-help using r-project.org> wrote:
>Hello All,
>
>wonder if you have a suggestion for the following:
>
>we have
>a<-data.frame(ID=c(1,2,3,4,5,6,7),date=as.POSIXct(seq(as.Date('2011-01-01'),as.Date('2011-01-07'),by
>= 1),format='%m/%d/%Y %H:%M'),z=rnorm(7,1,1))
>b<-data.frame(ID=c(1,2,3,11,12,13,14,15),date=as.POSIXct(seq(as.Date('2011-01-01'),as.Date('2011-01-08'),by
>= 1),format='%m/%d/%Y %H:%M'),z=rnorm(8,1,1))
>c<-data.frame(ID=c(1,2,3,4,5,6,7,8,9,10),date=as.POSIXct(c(seq(as.Date('2011-01-01'),as.Date('2011-01-05'),by
>= 1),seq(as.Date('2011-01-11'),as.Date('2011-01-15'),by =
>1)),format='%m/%d/%Y %H:%M'),z=rnorm(10,1,1))
>d<-data.frame(ID=c(1,2,3,21,22,23,24,25,26,27,28),date=as.POSIXct(c(as.Date('2011-01-01'),as.Date('2011-11-01'),as.Date('2011-01-03'),seq(as.Date('2011-01-01'),as.Date('2011-01-08'),by
>= 1)),format='%m/%d/%Y %H:%M'),z=rnorm(11,1,1))
>
>
>#this function will do the obvious and give the IDs that are in all of
>the data frames based on the ID column
>
>intersect_all <- function(a,b,...){
>  Reduce(intersect, list(a,b,...))
>}
>
>intersect_all(a$ID,b$ID,c$ID,d$ID)
>
>
>#I would like to extend this (or use another function) where the
>function would give all the rows (ie based on both columns as a
>condition) that are in all of the data frames, so the result should be
>as below as these 2 rows are in all of the data frames (the fact that
>the rows that are common in all data frames ie 1 and 3 in my example
>are I only set up for the sake of convenience, in reality their row
>number in each of the data frames may be different) . The value of z is
>of no particular importance, but once the common rows are identified I
>would want to subset the data frames to get these results:
>
>a[c(1,3),]
>b[c(1,3),]
>c[c(1,3),]
>d[c(1,3),]
>
>much appreciate your input,
>
>thanks
>
>Andras 
>
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-- 
Sent from my phone. Please excuse my brevity.  
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