[R] Help with Identify the number (Count) of values that are less than 5 char and replace with 99999
Rui Barradas
ru|pb@rr@d@@ @end|ng |rom @@po@pt
Mon Dec 16 18:04:42 CET 2019
Hello,
To count the number of variables with less than 5 characters, use nchar
and table or aggregate.
Since nchar needs a character vector and you have a factor, first
convert with as.character.
edt1a$ProcedureCode <- as.character(edt1a$ProcedureCode)
1.
Now any of the next 3 instructions will table the vector by number of
characters.
table(nchar(edt1a$ProcedureCode))
aggregate(ProcedureCode ~ nchar(ProcedureCode), edt1a, length)
tapply(edt1a$ProcedureCode, nchar(edt1a$ProcedureCode), length)
2.
If you want to change the values with less than 5 chars or all NA's to
"99999", a vectorized logical operation is a good way of doing it.
n <- nchar(edt1a$ProcedureCode) < 5
na <- is.na(edt1a$ProcedureCode)
edt1a$ProcedureCode[n | na] <- "99999"
Now back to factor, with the new level "99999".
edt1a$ProcedureCode <- factor(edt1a$ProcedureCode)
Hope this helps,
Rui Barradas
Às 13:24 de 16/12/19, Bill Poling escreveu:
> #RStudio Version 1.2.5019
> sessionInfo()
> # R version 3.6.1 (2019-07-05)
> # Platform: x86_64-w64-mingw32/x64 (64-bit)
> # Running under: Windows 10 x64 (build 17134)
>
> Good morning. I have a factor that contains 1,418,303 Clinical Procedure Code (CPT).
>
> A CPT Code is 5 char. However, among my data there are many values that are less, 2, 3, 4, as well as NA's
> I get the count of NA's from the str() function = 58,481
>
> Using the nchar function (I converted the Factor to a character column first) I get the first 1K values.
> (Perhaps this is not necessary with an alternative function?)
> # edt1a$ProcedureCode1 <- levels(edt1a$ProcedureCode)[edt1a$ProcedureCode]
> #https://www.rdocumentation.org/packages/base/versions/3.6.2/topics/nchar
>
> [989] 5 5 5 5 5 5 5 5 5 5 5 5
> [ reached getOption("max.print") -- omitted 1417303 entries ]
>
> What I would like to do is:
>
> 1. Identify the number (Count) of values that are less than 5 char (i.e. 2 char = 150, 3 char = 925, 4 char = 1002)
> Probably look something like this:
> |Var1 | Freq|
> |:------|-----:|
> |2 | 150 |
> |3 | 925 |
> |4 | 1002|
> 2. Replace with 99999 as well as replace the NA's with 99999
>
> head(edt1a$ProcedureCode1, n= 50) #Not apparent in top 50 but they are there
> [1] "44207" "99478" "99478" "99479" "98927" "01610" "99396" "81025" "64645" "99478" "99479" "99479" "99479" "99479" "99479" "97110" "J1885" "19081" "99479"
> [20] "99478" "99479" "99479" "99479" "99213" "99213" "98927" "96372" "92507" "99479" "99478" "99478" "99478" "99479" "77065" "19083" "95874" "99244" "A7034"
> [39] "A7046" "71275" "J1170" "90471" "87591" "80053" "98926" "A4649" "A7033" "43644" "85025" "73080"
>
> str(edt1a$ProcedureCode) #Factor w/ 6244
> Factor w/ 6244 levels "0003M","00100",..: 1775 4732 4732 4733 4586 147 4708 3108 2400 4732 ...
> str(edt1a$ProcedureCode1)
> chr [1:1418303] "44207" "99478" "99478" "99479" "98927" "01610" "99396" "81025" "64645" "99478" "99479" "99479" "99479" "99479" "99479" "97110" "J1885" ...
>
> #Some examples from using sink and knitr
>
> sink("ProcCodeV2.txt")
> knitr::kable(table(edt1a$ProcedureCode1))
> closeAllConnections()
>
> |Var1 | Freq|
> |:------|-----:|
> |0003M | 1|
> |0110 | 4|<--
> |0111 | 5|<--
> |01112 | 11|
> |0112 | 14|<--
> |01120 | 3|
> |0113 | 2|<--
> |01130 | 1|
> |0114 | 1|<--
> |01160 | 3|
> |01170 | 4|
> |0120 | 7|<--
> |01200 | 8|
> |01202 | 26|
> |0121 | 7|<--
> |01210 | 19|
> |01214 | 125|
> |01215 | 5|
> |0122 | 2|<--
> |01220 | 2|
> |01230 | 11|
> |0124 | 5|<--
> |171 | 1|<--
> |17106 | 6|
>
> Thank you for any help.
>
> WHP
>
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