[R] Help with factor column replacement value issue

Michael Dewey li@t@ @ending from dewey@myzen@co@uk
Fri Nov 16 17:16:22 CET 2018


Dear Bill

When you do your step of replacing lower case l with upper case L the 
level still stays in the factor even though it is empty. If that is a 
nuisance x <- factor(x) will drop the unused levels. There are other 
ways of doing this.

Michael

On 16/11/2018 15:38, Bill Poling wrote:
> Hello:
> 
> I am running windows 10 -- R3.5.1 -- RStudio Version 1.1.456
> 
> I would like to know why when I replace a column value it still appears in subsequent routines:
> 
> My example:
> 
> r1$B1 is a Factor: It is created from the first character of a list of CPT codes, r1$CPT.
> 
> head(r1$CPT, N= 25)
> [1] A4649 A4649 C9359 C1713 A0394 A0398
> 903 Levels: 00000 00001 00140 00160 00670 00810 00940 01400 01470 01961 01968 10160 11000 11012 11042 11043 11044 11045 11100 11101 11200 11201 11401 11402 ... l8699
> 
> str(r1$CPT)
>   Factor w/ 903 levels "00000","00001",..: 773 773 816 783 739 741 743 739 739 741 ...
> 
> 
> And I want only those CPT's with leading alpha char in this column so I set the numeric leading char to Z
> 
> r1$B1 <- str_sub(r1$CPT,1,1)
> 
> r1$B1 <- as.factor(r1$B1) #Redundant
> levels(r1$B1)[levels(r1$B1) %in%  c('1','2','3','4','5','6','7','8','9','0')] <- 'Z'
> 
> When I check what I have done I find l & L
> 
> unique(r1$B1)
> #[1] A C Z L G Q U J V E S l D P
> #Levels: Z A C D E G J l L P Q S U V
> 
> So I change l to L
> r1$B1[r1$B1 == 'l'] <- 'L'
> 
> When I check again I have l & L but l = 0
> table(r1$B1)
> #   Z          A          C      D     E     G      J           l     L         P     Q     S     U     V
> #19639  1673   546     2     8   147   281     0    664     1    64    36   114    14
> 
> When I go to find those rows as if they existed, they are not accounted for?
> 
> tmp <- subset(r1, B1 == "l")
> print(tmp)
> Empty data.table (0 rows) of 9 cols: SavingsReversed,productID,ProviderID,PatientGender,ModCnt,Editnumber2...
> 
> And I have actually visually inspected the whole darn column, sheesh!
> 
> So I ignore it temporarily.
> 
> Now later on it resurfaces in a tutorial I am following for caret pkg.
> 
> preProcess(r1b, method = c("center", "scale"),
>             thresh = 0.95, pcaComp = NULL, na.remove = TRUE, k = 5,
>             knnSummary = mean, outcome = NULL, fudge = 0.2, numUnique = 3,
>             verbose = FALSE, freqCut = 95/5, uniqueCut = 10, cutoff = 0.9,
>             rangeBounds = c(0, 1))
> # Warning in preProcess.default(r1b, method = c("center", "scale"), thresh = 0.95,  :
> #                                 These variables have zero variances: B1l  <-------------yes this is a remnant of the r1$B1 clean-up
> #                               Created from 23141 samples and 22 variables
> #
> #                               Pre-processing:
> #                                 - centered (22)
> #                                 - ignored (0)
> #                                 - scaled (22)
> 
> 
> So my questions are, in consideration of regression modelling accuracy:
> 
> Why is this happening?
> How do I remove it?
> Or is it irrelevant and leave it be?
> 
> As always, thank you for you support.
> 
> WHP
> 
> 
> 
> 
> 
> 
> 
> 
> 
> 
> 
> 
> Confidentiality Notice This message is sent from Zelis. ...{{dropped:13}}
> 
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> 

-- 
Michael
http://www.dewey.myzen.co.uk/home.html



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