[R] find the permutation function of a sorting
Jeff Newmiller
jdnewm|| @end|ng |rom dcn@d@v|@@c@@u@
Wed May 23 05:29:04 CEST 2018
Perhaps the question was "what is indexing"?
On May 23, 2018 5:06:39 AM GMT+02:00, David Winsemius <dwinsemius using comcast.net> wrote:
>
>
>> On May 22, 2018, at 10:57 PM, John <miaojpm using gmail.com> wrote:
>>
>> Thanks, David.
>> I got the answer from the web.
>> Is there any easy way to permute a set (e.g., a set of characters) by
>the permutation it returns? Thanks,
>>
>>
>> > x <- c(10,7,4,3,8,2)
>> > sort(x, index.return=TRUE)
>> $x
>> [1] 2 3 4 7 8 10
>>
>> $ix
>> [1] 6 4 3 2 5 1
>>
>
>I don't understand what is being requested. The $ix value is the same
>as the one returned `by order`.
>
>David.
>
>
>> 2018-05-23 10:49 GMT+08:00 David Winsemius <dwinsemius using comcast.net>:
>>
>>
>> > On May 22, 2018, at 10:06 PM, John <miaojpm using gmail.com> wrote:
>> >
>> > Hi,
>> >
>> > Is there any way to find the permutation function of the sorting
>and to
>> > apply the function (or its inverse) elsewhere?
>> >
>> > For example, the following permutation function from the sorting
>in the
>> > matrix form is
>> > c(1,2,3), c(2,1,3)
>> >
>> >> sort(c("bc","ac","dd"))
>> > [1] "ac" "bc" "dd"
>> >
>>
>> I think you are asking for the `order` function.
>>
>> > I try to find it in the permutations/permute package, but I can't
>find it
>> >
>> > John
>> >
>> > [[alternative HTML version deleted]]
>>
>>
>
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