[R] subsetting lists....

MacQueen, Don m@cqueen1 @end|ng |rom ||n|@gov
Mon Jun 18 23:52:32 CEST 2018

```The unlist solution is quite clever.

But I will note that none of the solutions offered so far succeed if the input is, for example,

YH <- list(1:5, letters[1:3], 1:7)
iuhV <- c(2,2,4)

and the desire is to return a list whose elements are of the same types as the input list. Which would be the sensible thing to do if the input list mixes types.

(Note that the output structure was not specified in the original question, nor was it stated whether the input list could mix types)

unlist(YH, recursive = FALSE, use.names = FALSE)[cumsum( lengths(YH)) - lengths(YH) + iuhV]
[1] "2" "b" "4"

However,

> lapply( 1:length(YH), function(i) { YH[[i]][iuhV[i]]})
[[1]]
[1] 2

[[2]]
[1] "b"

[[3]]
[1] 4

--
Don MacQueen
Lawrence Livermore National Laboratory
7000 East Ave., L-627
Livermore, CA 94550
925-423-1062
Lab cell 925-724-7509

﻿On 6/18/18, 10:00 AM, "R-help on behalf of Berry, Charles" <r-help-bounces using r-project.org on behalf of ccberry using ucsd.edu> wrote:

> On Jun 18, 2018, at 4:15 AM, akshay kulkarni <akshay_e4 using hotmail.com> wrote:
>
> correction....I want the method without a for loop

Here are two. The first is more readable, but the second is 5 times faster.

mapply("[", YH, iuhV)

unlist(YH, recursive = FALSE, use.names = FALSE)[cumsum( lengths(YH)) - lengths(YH) + iuhV]

HTH,

Chuck

> ________________________________
> From: akshay kulkarni <akshay_e4 using hotmail.com>
> Sent: Monday, June 18, 2018 4:25 PM
> To: R help Mailing list
> Subject: subsetting lists....
>
> dear members,
>                            I have list YH and index vector iuhV. I want to select iuhV[1] from YH[[1]], iuhv[2] from YH[[2]], iuhv[3] from YH[[3]]......iuhv[n] from YH[[n]]...
>
> How to do this?
> I searched SO and the internet but was bootless....
>
> Very many thanks for your time and effort.....
> Yours sincerely,
> AKSHAY M KULKARNI
>
> 	[[alternative HTML version deleted]]
>

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