[R] Storing tableGrobs in a list

Jeff Newmiller jdnewm|| @end|ng |rom dcn@d@v|@@c@@u@
Thu Jun 14 08:01:28 CEST 2018


and read the discussions of indexing in the Introduction to R document that comes with R. Also, find a way to predict the number of elements you will need as making this a habit will pay off big time when you work with large amounts of data:

L1<-vector( "list", N )
for (i in seq.int( N )) {
   L1[[i]] <-tableGrob( ... )

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On June 13, 2018 4:43:21 PM HST, Stats Student <stats.student4647 using gmail.com> wrote:
>Hi, I'm trying to generate tableGrobs in a loop, store them in a list
>so I
>can use it in a call to gtable_combine().
>for (i in seq( ... )) {
>   L1[i] <-tableGrob( ... )
>gtable_combine(L1, along=1)
>On the assignment inside the loop, I get "number of items to replace is
>a multiple of replacement length" which I'm guessing has to do with the
>tableGrob object not "fitting" in the list but am not sure how to fix
>Thanks in advance for any pointers.
>	[[alternative HTML version deleted]]
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Sent from my phone. Please excuse my brevity.

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