[R] GGPlot plot

[Jim Lemon]

Hi Francesca,
This looks like a fairly simple task. Try this:

fpdf<-read.table(text="PASP   SUBJC
 0          0
 4          1
 0          0
 8          0
 4          0
 0          1
 0          1",
 header=TRUE)
# get the number of positive PASP results by group
ppos<-by(fpdf$SUBJC,fpdf$PASPpos,sum)
# get the number of subjects per group
spg<-c(sum(fpdf$SUBJC==0),sum(fpdf$SUBJC==1))
barplot(ppos/spg,names.arg=c(0,1),xlab="Group",
 ylab="Proportion PASP > 0",main="Proportion of PASP positive by group")

Jim

On Thu, Jul 19, 2018 at 2:47 AM, Francesca <francesca.pancotto using gmail.com> wrote:
> Dear R help,
>
> I am new to ggplot so I apologize if my question is a bit obvious.
>
> I would like to create a plot where a compare the fraction of the values of a variable called PASP out of the number of subjects, for two groups of subject codified with a dummy variable called SUBJC.
>
> The variable PASP is discrete and only takes values 0,4,8..
>
> My data are as following:
>
>
>
> PASP   SUBJC
>
>
>
> 0          0
>
> 4          1
>
> 0          0
>
> 8          0
>
> 4          0
>
> 0          1
>
> 0          1
>
> .           .
>
> .           .
>
> .           .
>
>
>
>
> I would like to calculate the fraction of positive levels of PASP out of the total number of observations, divided per values of SUBJ=0 and 1. I am new to the use of GGPlot and I do not know how to organize the data and what to use to summarize these data as to obtain a picture as follows:
>
>
>
>
>
> I hope my request is clear. Thanks for any help you can provide.
>
> Francesca
>
>
>
> ______________________________________________
> R-help using r-project.org mailing list -- To UNSUBSCRIBE and more, see
> https://stat.ethz.ch/mailman/listinfo/r-help
> PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
> and provide commented, minimal, self-contained, reproducible code.