[R] Identyfing rows with specific conditions
Allaisone 1
allaisone1 at hotmail.com
Mon May 22 11:11:05 CEST 2017
Hi Again..,
All of my 2 tables are data.frames and the order of meals does not matter. Meal A =2 and Meal B= 15 is the same as Meal A=15 and Meal B= 2.
________________________________
From: Bert Gunter <bgunter.4567 at gmail.com>
Sent: 22 May 2017 03:19:57
To: Allaisone 1
Cc: r-help at r-project.org
Subject: Re: [R] Identyfing rows with specific conditions
More clarification:
Are your "tables" matrices or data frames? (If you don't know what
this means, you need to spend a little time with a e.g. web tutorial
to learn).
Also, does Meal A Meal B order count? -- i.e. is Meal A = 2, Meal B =
15 the same as Meal A = 15 and Meal B = 2? This is important.
Cheers,
Bert
Bert Gunter
"The trouble with having an open mind is that people keep coming along
and sticking things into it."
-- Opus (aka Berkeley Breathed in his "Bloom County" comic strip )
On Sun, May 21, 2017 at 5:10 PM, Allaisone 1 <allaisone1 at hotmail.com> wrote:
>
> Hi All..,
>
> I have 2 tables. The first one contains 2 columns with the headers say "meal A code" & "meal B code " in a table called "Meals" with 2000 rows each of which with a different combination of meals(unique combination per row).
>
>
>>Meals
>
> meal A code meal B code
>
> 1 34 66
>
> 2 89 39
>
> 3 25 77
>
> The second table(customers) shows customers ids in the first column with Meals codes(M) next to each customer. There are about 300,000 customers (300,000 rows).
>
>> Customers
> 1 2 3 4 ..30
> id M1 M2 M3
> 1 15 77 34 25
> 2 11 25 34 39
> 3 85 89 25 77
> .
> .
> 300,000
>
> I would like to identify all customers ids who have had each meal combination in the first table so the final output would be the first table with ids attached next to each meal combination in each row like this:
>
>>IdsMeals
>
>
> MAcode MBcode ids
>
> 1 34 39 11
>
> 2 25 34 15 11
>
> 3 25 77 15 85
>
> Would you please suggest any solutions to this problem?
>
> Regards
>
> [[alternative HTML version deleted]]
>
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