[R] About calculating average values from several matrices

[lily li]

I'm trying to get a new dataframe or whatever to call, which has the same
structure with each file as listed above. For each cell in the new
dataframe or the new file, it is the average value from former dataframes
at the same location. Thanks.

On Tue, May 9, 2017 at 8:41 AM, Doran, Harold <HDoran at air.org> wrote:

> Are you trying to take the mean over all cells, or over rows/columns
> within each dataframe. Also, are these different dataframes stored within a
> list or are they standalone?
>
>
>
> -----Original Message-----
> From: R-help [mailto:r-help-bounces at r-project.org] On Behalf Of lily li
> Sent: Tuesday, May 09, 2017 10:39 AM
> To: R mailing list <r-help at r-project.org>
> Subject: [R] About calculating average values from several matrices
>
> Hi R users,
>
> I have a question about manipulating the data.
> For example, there are several such data frames or matrices, and I want to
> calculate the average value from all the data frames or matrices. How to do
> it? Also, should I convert them to data frame or matrix first? Right now,
> when I use typeof() function, each one is a list.
>
> file1
>             jan   feb   mar   apr   may   jun   jul   aug   sep   oct   nov
>
> app1   1.1   1.2    0.8    0.9   1.3    1.5   2.2   3.2   3.0    1.2   1.1
> app2   3.1   3.2    2.8    2.5   2.3    2.5   3.2   3.0   2.9    1.8   1.8
> app3   5.1   5.2    3.8    4.9   5.3    5.5   5.2   4.2   5.0    4.2   4.1
>
> file2
>             jan   feb   mar   apr   may   jun   jul   aug   sep   oct   nov
>
> app1   1.9   1.5    0.5    0.9   1.2    1.8   2.5   3.7   3.2    1.5   1.6
> app2   3.5   3.7    2.3    2.2   2.5    2.0   3.6   3.2   2.8    1.2   1.4
> app3   5.5   5.0    3.5    4.4   5.4    5.6   5.3   4.4   5.2    4.3   4.2
>
> file3 has the similar structure and values...
>
> There are eight such files, and when I use the function mean(file1, file2,
> file3, ..., file8), it returns the error below. Thanks for your help.
>
> Warning message:
> In mean.default(file1, file2, file3, file4, file5, file6, file7,  :
>   argument is not numeric or logical: returning NA
>
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>
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