[R] Suggestions for vectorizing/double loop
thierry.onkelinx at inbo.be
Mon Jan 23 14:12:44 CET 2017
Assuming that oldnames and newnames are character (and not factor), the
just use stringsAsFactors = FALSE. That will save you from having to
convert the factors back to character.
data.frame(oldnames, newnames, stringsAsFactor = FALSE)
ir. Thierry Onkelinx
Instituut voor natuur- en bosonderzoek / Research Institute for Nature and
team Biometrie & Kwaliteitszorg / team Biometrics & Quality Assurance
To call in the statistician after the experiment is done may be no more
than asking him to perform a post-mortem examination: he may be able to say
what the experiment died of. ~ Sir Ronald Aylmer Fisher
The plural of anecdote is not data. ~ Roger Brinner
The combination of some data and an aching desire for an answer does not
ensure that a reasonable answer can be extracted from a given body of data.
~ John Tukey
2017-01-23 13:28 GMT+01:00 Luanna Dixson <justanotherdigression op gmail.com>:
> I need to rename a bunch of files, by searching for string matches in a
> list. Each list element containings a character with the old filename that
> I want to match to, and the new file name that I want to rename by.
> For instance, here filename '1001.xls' should match to list[]$oldname
> and I want to rename it to 'newa.xls' from list[]$newname.
> The actual new file names I have will feature a random alphanumeric number
> and the list will have a length of ~600.
> # files I want to rename
> files with old file name =c('1001.xls', '1002.xls')
> # list with old file names and new file names
> oldnames=c('1001', '1002', '1003')
> newnames=c('newa', 'newb', 'newc')
> list <- split(df, rownames(df))
> # turn list elements in character
> for(i in 1:length(list)) list[[i]]$oldnames=as.
> for(i in 1:length(list)) list[[i]]$newnames=as.
> I heard that it would be better to vectorize this than trying to do a
> double loop so if someone could give me a hint about how to do this I would
> be very grateful!
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