[R] Lubdridate: subset based on hour and minute

[Roy Mendelssohn - NOAA Federal]

Hi Joe:

See below.
> On Jan 2, 2017, at 12:01 PM, Joe Ceradini <joeceradini at gmail.com> wrote:
> 
> Hi folks,
> 
> I must be missing something obvious/painfully simple here....
> 
> How do I subset a time vector based on hours AND minutes? So, in this
> example, I want all time greater than 10:00, i.e., 10:30 and 11:00.
> I'm working with lubridate which separates the hours and minutes into
> separate slots.
> 
> require(lubridate)
> 
> test <- hm(c("9:30", "10:00", "10:30", "11:00"))
> test
> [1] "9H 30M 0S"  "10H 0M 0S"  "10H 30M 0S" "11H 0M 0S"
> 
> This gets 11 but not 1030
> test[test at hour > 10]
> [1] "11H 0M 0S"
> 
> This gets 1030 but not 11
> test[test at hour > 9 & test at minute > 0]
> [1] "10H 30M 0S"

 test[test at hour > 9]
[1] "10H 0M 0S"  "10H 30M 0S" "11H 0M 0S" 


You are using a logical "and" in your test - so the condition "test at minute > 0" isn't met for 11:00 and therefore it doesn't show up. as both conditions must be met  You could also do:

> test[test at hour >= 10]
[1] "10H 0M 0S"  "10H 30M 0S" "11H 0M 0S" 

-HTH,

Roy

> 
> Thanks and happy new year!
> Joe
> 
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Roy Mendelssohn
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NOAA/NMFS
Environmental Research Division
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