[R] define a list with names as variables

[Bert Gunter]

> f <- function(foo,bar) structure(list(bar),names =foo)

> f("hello","world")
$hello
[1] "world"

Cheers,
Bert


Bert Gunter

"The trouble with having an open mind is that people keep coming along
and sticking things into it."
-- Opus (aka Berkeley Breathed in his "Bloom County" comic strip )


On Fri, Aug 4, 2017 at 6:12 AM, Jeff Newmiller <jdnewmil at dcn.davis.ca.us> wrote:
> You can wrap the list-creating function call (e.g. lapply) in a call to ?setNames, or you can use the ?map function from the purrr package.
> --
> Sent from my phone. Please excuse my brevity.
>
> On August 4, 2017 3:14:44 AM PDT, Ulrik Stervbo <ulrik.stervbo at gmail.com> wrote:
>>Hi Giovani,
>>
>>I would create an unnamed list and set the names after.
>>
>>Best,
>>Ulrik
>>
>>On Fri, 4 Aug 2017 at 12:08 Giovanni Gherdovich
>><g.gherdovich at gmail.com>
>>wrote:
>>
>>> Hello,
>>>
>>> I'm having troubles defining a list where names are variables (of
>>type
>>> character). Like this, which gives "foo" instead of "world" (the way
>>I
>>> meant it is that "world" is the value of the variable foo). Any hint?
>>>
>>> > f <- function(foo, bar) { list(foo = bar) }
>>> > x <- f("hello", "world")
>>> > names(x)
>>> [1] "foo"
>>>
>>>
>>> Thanks,
>>> Giovanni
>>>
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>>
>>       [[alternative HTML version deleted]]
>>
>>______________________________________________
>>R-help at r-project.org mailing list -- To UNSUBSCRIBE and more, see
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>>PLEASE do read the posting guide
>>http://www.R-project.org/posting-guide.html
>>and provide commented, minimal, self-contained, reproducible code.
>
> ______________________________________________
> R-help at r-project.org mailing list -- To UNSUBSCRIBE and more, see
> https://stat.ethz.ch/mailman/listinfo/r-help
> PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
> and provide commented, minimal, self-contained, reproducible code.