[R] Issue on LGP solving

Dr. Debasis Ghosh deb at debasis.in
Tue Sep 20 15:58:55 CEST 2016


Thanks Petr!! However, I found in the goalprog package I found "achievements" as "a  data frame with the deviation variables for each objective together with the
priority level". I defined

> p1<-c(2,0,0,0,0,0)
> p2 <- c(0,0,0,0,1,0)
> p3<- c(0,0,0,0,0,1)
> achievement <- data.frame(p1,p2,p3)

Here p1, p2 and p3 are the 3 priority levels. 

I understand the problem is at "achievement" data frame. To your point, data frame with four named columns (objective, priority, p and n), how these four columns are defined ? 

Appreciate your time Petr. Thanks again!! 

Regards,
Debasis Ghosh, Ph.D

-----Original Message-----
From: PIKAL Petr [mailto:petr.pikal at precheza.cz] 
Sent: Tuesday, September 20, 2016 6:55 AM
To: Dr. Debasis Ghosh; R-help at r-project.org
Subject: RE: [R] Issue on LGP solving

Hi

Just a wild guess. Achievement in the goalprog package is data frame with four named columns (objective, priority, p and n).

Your achievement is 3 column data.frame with names p1, p2 and p3.

Maybe data frame with defined structure is required.

Cheers
Petr


> -----Original Message-----
> From: R-help [mailto:r-help-bounces at r-project.org] On Behalf Of Dr.
> Debasis Ghosh
> Sent: Tuesday, September 20, 2016 8:12 AM
> To: R-help at r-project.org
> Subject: [R] Issue on LGP solving
>
> I was solving a LGP problem which is very basic.
>
>
>
> Find x0 = [x1; x2], n0 = [n1; n2; n3] and p0 = [p1; p2; p3] that minimize a =
> [(2p1); (n2); (n3)]
>
> The objectives are as follows
>
> 10x1 + 15x2 + n1 - p1 = 40
>
> 100x1 + 100x2 + n2 - p2 = 1000
>
> x2 + n3 - p3 = 7
>
> x; n; p >= 0
>
> The solution is x' = [4; 0] and a = [0; 600; 7]
>
>
>
>
>
> > local({pkg <- select.list(sort(.packages(all.available =
> TRUE)),graphics=TRUE)
>
> + if(nchar(pkg)) library(pkg, character.only=TRUE)})
>
> > local({pkg <- select.list(sort(.packages(all.available =
> TRUE)),graphics=TRUE)
>
> + if(nchar(pkg)) library(pkg, character.only=TRUE)})
>
>
>
>
>
> > coeff<-matrix (c(10,15,100,100,0,1), nrow=3, ncol=2, byrow=TRUE)
>
> > target<-c(40,1000,7)
>
> > p1<-c(2,0,0,0,0,0)
>
> > p2 <- c(0,0,0,0,1,0)
>
> > p3<- c(0,0,0,0,0,1)
>
> > achievement <- data.frame(p1,p2,p3)
>
> > achievement
>
>   p1 p2 p3
>
> 1  2  0  0
>
> 2  0  0  0
>
> 3  0  0  0
>
> 4  0  0  0
>
> 5  0  1  0
>
> 6  0  0  1
>
> > llgp(coeff,target,achievement)
>
>
>
> Do you have any idea why I am seeing below error ?
>
>
>
>
>
> Error in matrix(0, nrow = levels, ncol = nonbasics) :
>
>   invalid 'nrow' value (too large or NA)
>
> In addition: Warning messages:
>
> 1: In max(achievements$priority) :
>
>   no non-missing arguments to max; returning -Inf
>
> 2: In matrix(0, nrow = levels, ncol = nonbasics) :
>
>   NAs introduced by coercion to integer range
>
>
>
> Regards,
>
> Debasis Ghosh, Ph.D
>
>
>
>
>       [[alternative HTML version deleted]]
>
> ______________________________________________
> R-help at r-project.org mailing list -- To UNSUBSCRIBE and more, see
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> PLEASE do read the posting guide http://www.R-project.org/posting-
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> and provide commented, minimal, self-contained, reproducible code.

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