[R] “log-rank test” and “Kaplan Meier actuarial plots (time to event curve)”

Steven Stoline sstoline at gmail.com
Sat Oct 8 00:56:10 CEST 2016


Dear All:



I do need your help with the “log-rank test” and “Kaplan Meier actuarial
plots (time to event curve)” with adding the confidence intervals bands for
the average score for each time to the curve of each group.


*Group variable:* 1 = group 1, 2 = group 2


*Time points:* time1, time2, time3, time4, time5


The goal is to compare the average scores of the two groups at each time
point and obtain the Kaplan Meier actuarial plots (time to event curve) for
the 5 time points for both groups in the plot.



Please use the following data for the test.


time1    time2    time3    time4    time5    groups

0              0              1              1              1              1

0              4              0              1              1              1

0              0              3              1              1              1

0              2              0              1              1              1

0              0              3              0              0              1

0              0              0              1              2              1

0              1              1              1
1

0              0              2              1              1              1

0              3              1              1              1              1

0              0              0              1
1

0              0              1              0              0              1

0              0              0              1              1              1

0              1              1              0              1              1

0              0              1              3              4              1

0              1              0              0              0              1

0              1              1              1              2              1

0              1              1              4              1              1

0              0              0              0
1

0              2              1              1              2              1


2

0              0              0              0              0              2


2

0
2

0              0              3              2              2              2

0              3              0              1              1              2

0              0              1              1              1              2

0
2

0              0              0              1              1              2

0              1              2              0              1              2

0              0              1              1
2

0              0              1              1              2              2

0              1              1              1              1              2

0              0              0              1              1              2

0              0              1              1              1              2


2

0              2              2              1
2

0              0              1              1
2

0              0              0              0              0              2

0              3              3              1              2              2

0              1              1              1
2

0              0              0              1              1              2

0              1              1              1              4              2

0              1              1              1              1              2

0              1              2              1              3              2





Thank you in advance

steve


-------------------------
Steven M. Stoline
sstoline at gmail.com

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