[R] aggregate dataframe by multiple factors

Karim Mezhoud kmezhoud at gmail.com
Sun Nov 20 14:28:22 CET 2016


Sorry for the delay,
Many Thanks for Mr. David and Mr. Petr
I thinked  to use "sort" function to arrange chronologically  value by
'date' (without 'date' is colnames) of each variables (DCE, DP).


The solution of David seems to be simple to understand with "unlist"
function.
The solution of Petr seems to be fancy. I did not find document  about "I"
argument for aggregate function.

How can know which value for which date?

I will save the reshaping/ordering dataframe  for later use.
Many Thanks,
Karim


On Fri, Nov 18, 2016 at 11:34 AM, PIKAL Petr <petr.pikal at precheza.cz> wrote:

> Hi
>
> same result can be achieved by
>
> dat.ag<-aggregate(dat[ , c("DCE","DP")], by= list(dat$first.Name,
> dat$Name, dat$Department) , "I")
>
> Sorting according to the first row seems to be quite tricky. You could
> probably get closer by using some combination of split and order and
> arranging back chunks  of data
>
> ooo1<-order(split(dat$DCE,interaction(dat$first.Name, dat$Name,
> dat$Department, drop=T))[[1]])
> data.frame(sapply(split(dat$DCE,interaction(dat$first.Name, dat$Name,
> dat$Department, drop=T)), rbind))[ooo1,]
>   Ancient.Nation.QLH Amish.Wives.TAS Auction.Videos.YME
> 2               0.28              NA                 NA
> 4               0.28              NA                 NA
> 1               0.54            0.59               0.57
> 3               0.54            0.59               0.57
>
> however I wonder why the order according to the first row is necessary if
> all NAs are on correct positions?
>
> Cheers
> Petr
>
>
> > -----Original Message-----
> > From: R-help [mailto:r-help-bounces at r-project.org] On Behalf Of David
> > Winsemius
> > Sent: Friday, November 18, 2016 9:30 AM
> > To: Karim Mezhoud <kmezhoud at gmail.com>
> > Cc: r-help at r-project.org
> > Subject: Re: [R] aggregate dataframe by multiple factors
> >
> >
> > > On Nov 17, 2016, at 11:27 PM, Karim Mezhoud <kmezhoud at gmail.com>
> > wrote:
> > >
> > > Dear all,
> > >
> > > the dat  has missing values NA,
> > >
> > >    first.Name   Name Department  DCE   DP       date
> > > 5      Auction Videos        YME 0.57 0.56 2013-09-30
> > > 18       Amish  Wives        TAS 0.59 0.56 2013-09-30
> > > 34     Ancient Nation        QLH 0.54 0.58 2013-09-30
> > > 53     Auction Videos        YME   NA   NA 2013-12-28
> > > 66       Amish  Wives        TAS   NA   NA 2013-12-28
> > > 82     Ancient Nation        QLH 0.28 0.29 2013-12-28
> > > 102    Auction Videos        YME 0.57 0.56 2014-03-30
> > > 115      Amish  Wives        TAS 0.59 0.56 2014-03-30
> > > 131    Ancient Nation        QLH 0.54 0.58 2014-03-30
> > > 150    Auction Videos        YME   NA   NA 2014-06-28
> > > 163      Amish  Wives        TAS   NA   NA 2014-06-28
> > > 179    Ancient Nation        QLH 0.28 0.29 2014-06-28
> > >
> > >
> > > agg <- as.data.frame(aggregate(dat[ , c("DCE","DP")], by=
> > > list(dat$first.Name, dat$Name, dat$Department) , "sort"))
> >
> > The closest I could get on a few attempts was:
> >
> > (agg <- as.data.frame(aggregate(dat[ , c("DCE","DP")], by=
> > list(dat$first.Name, dat$Name, dat$Department) , function(d) {
> unlist(d)}))
> >  )
> >
> >   Group.1 Group.2 Group.3 DCE.1 DCE.2 DCE.3 DCE.4 DP.1 DP.2 DP.3 DP.4
> > 1 Ancient  Nation     QLH  0.54  0.28  0.54  0.28 0.58 0.29 0.58 0.29
> > 2   Amish   Wives     TAS  0.59    NA  0.59    NA 0.56   NA 0.56   NA
> > 3 Auction  Videos     YME  0.57    NA  0.57    NA 0.56   NA 0.56   NA
> >
> > I think the sort operation might be somewhat ambiguous in this instance.
> I
> > tried:
> >
> >  (agg <- as.data.frame(aggregate(dat[ , c("DCE","DP")], by=
> > list(dat$first.Name, dat$Name, dat$Department) , function(d) {
> > unlist(lapply(d,sort))}))
> >  )
> >
> > With no success, not even a sorted result.
> >
> > --
> > David.
> > >
> > >
> > > agg has list of value. I would separate value in different columns.
> > >
> > >  Group.1 Group.2 Group.3                    DCE                     DP
> > > 1 Ancient  Nation     QLH 0.28, 0.28, 0.54, 0.54 0.29, 0.29, 0.58, 0.58
> > > 2   Amish   Wives     TAS             0.59, 0.59             0.56, 0.56
> > > 3 Auction  Videos     YME             0.57, 0.57             0.56, 0.56
> > >
> > > The  goal:
> > >
> > > Group.1 Group.2 Group.3  DCE.1 DCE.2 DCE.3  DCE.4  DP.1  DP.2  DP.3
> DP.4
> > > 1 Ancient  Nation     QLH    0.28     0.28    0.54     0.54     0.29,
> 0.29,
> > > 0.58, 0.58
> > > 2   Amish   Wives     TAS        NA     NA     0.59, 0.59           NA
> > > NA  0.56, 0.56
> > > 3 Auction  Videos     YME         NA   NA      0.57, 0.57
>  NA
> > > NA  0.56, 0.56
> > >
> > >
> > >
> > > dat <- structure(list(first.Name = structure(c(3L, 1L, 2L, 3L, 1L, 2L,
> > > 3L, 1L, 2L, 3L, 1L, 2L), .Label = c("Amish", "Ancient", "Auction",
> > > "Ax", "Bachelorette", "Basketball", "BBQ", "Cake", "Celebrity",
> > > "Chef", "Clean", "Colonial", "Comedy", "Comic", "Crocodile", "Dog",
> > > "Empire", "Extreme", "Farm", "Half Pint", "Hollywood", "House", "Ice
> > > Road", "Jersey", "Justice", "Love", "Mega", "Model", "Modern",
> > > "Mountain", "Mystery", "Myth", "New York", "Paradise", "Pioneer",
> > > "Queer", "Restaurant", "Road", "Royal", "Spouse", "Star", "Storage",
> > > "Survival", "The Great American", "Tool", "Treasure", "Wedding",
> > > "Wife"), class = "factor"), Name = structure(c(43L, 47L, 29L, 43L,
> > > 47L, 29L, 43L, 47L, 29L, 43L, 47L, 29L), .Label = c("Aliens",
> > > "Behavior", "Casino", "Casting Call", "Challenge", "Contest",
> > > "Crashers", "Crew", "Dad", "Dancing", "Date", "Disasters", "Dynasty",
> > > "Family", "Garage", "Greenlight", "Gypsies", "Haul", "Hot Rod",
> > > "Inventor", "Jail", "Job", "Justice", "Marvels", "Master", "Mates",
> > > "Model", "Moms", "Nation", "Ninja", "Patrol", "People", "Pitmasters",
> > > "Queens", "Rescue", "Rivals", "Room", "Rooms", "Rules", "Star",
> > > "Stars", "Superhero", "Videos", "VIP", "Wars", "Wishes", "Wives",
> > > "Wrangler"), class = "factor"), Department = structure(c(8L, 6L, 2L,
> > > 8L, 6L, 2L, 8L, 6L, 2L, 8L, 6L, 2L), .Label = c("HXW", "QLH", "RAR",
> > > "RYC", "SYI", "TAS", "VUV", "YME"), class = "factor"),
> > >    DCE = c(0.57, 0.59, 0.54, NA, NA, 0.28, 0.57, 0.59, 0.54,
> > >    NA, NA, 0.28), DP = c(0.56, 0.56, 0.58, NA, NA, 0.29, 0.56,
> > >    0.56, 0.58, NA, NA, 0.29), date = structure(c(15978, 15978,
> > >    15978, 16067, 16067, 16067, 16159, 16159, 16159, 16249, 16249,
> > >    16249), class = "Date")), description = "", row.names = c(5L, 18L,
> > > 34L, 53L, 66L, 82L, 102L, 115L, 131L, 150L, 163L, 179L), class =
> > > "data.frame", .Names = c("first.Name", "Name", "Department", "DCE",
> > > "DP", "date"))
> > >
> > >     [[alternative HTML version deleted]]
> > >
> > > ______________________________________________
> > > R-help at r-project.org mailing list -- To UNSUBSCRIBE and more, see
> > > https://stat.ethz.ch/mailman/listinfo/r-help
> > > PLEASE do read the posting guide
> > > http://www.R-project.org/posting-guide.html
> > > and provide commented, minimal, self-contained, reproducible code.
> >
> > David Winsemius
> > Alameda, CA, USA
> >
> > ______________________________________________
> > R-help at r-project.org mailing list -- To UNSUBSCRIBE and more, see
> > https://stat.ethz.ch/mailman/listinfo/r-help
> > PLEASE do read the posting guide http://www.R-project.org/posting-
> > guide.html
> > and provide commented, minimal, self-contained, reproducible code.
>
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