[R] how to use AND in grepl

[Tom Wright]

Actually not sure my previous answer does what you wanted. Using your
approach:

 t2pd=subset(df,grepl("t2",df$Command) & grepl("pd",df$Command))

Should work.

I think the regex pattern you are looking for is:

 Subset(df,grepl("(.* t2.*pd.* )|(.* pd.* t2.*)",df$Command)

On Sat, Apr 30, 2016, 7:07 PM Tom Wright <tom at maladmin.com> wrote:

> subset(df,grepl("t2|pd",x$Command))
>
>
> On Sat, Apr 30, 2016 at 2:38 PM, ch.elahe via R-help <r-help at r-project.org
> > wrote:
>
>> Hi all,
>>
>> I have one factor variable in my df and I want to extract the names from
>> it which contain both "t2" and "pd":
>>
>>   'data.frame': 36919 obs. of 162 variables
>>    $TE                :int 38,41,11,52,48,75,.....
>>    $TR                :int 100,210,548,546,.....
>>    $Command          :factor W/2229 levels
>> "_localize_PD","_localize_tre_t2","_abdomen_t1_seq","knee_pd_t1_localize","pd_local_abdomen_t2"...
>>
>> I have tried this but I did not get result:
>>
>>   t2pd=subset(df,grepl("t2",Command) & grepl("pd",Command))
>>
>>
>> does anyone know how to apply AND in grepl?
>>
>> Thanks
>> Elahe
>>
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>

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