[R] extracting months from a data

[Dalthorp, Daniel]

Or:

x <- c( "3-Oct", "10-Nov" )
format(as.Date(paste0(x,rep("-1970",length(x))),format='%d-%b-%Y'),'%b')

# the 'paste0' appends a year to the text vector
# the 'as.Date' interprets the strings as dates with format  10-Jun-2016
(e.g.)
# the 'format' returns a string with date in format '%b' (which is just the
name of the month)

On Wed, Mar 9, 2016 at 3:52 PM, Jeff Newmiller <jdnewmil at dcn.davis.ca.us>
wrote:

> Your dates are incomplete (no year) so I suggest staying away from the
> date functions for this. Read ?regex and ?sub.
>
> x <- c( "3-Oct", "10-Nov" )
> m <- sub( "^\\d+-([A-Za-z]{3})$", "\\1", x )
>
> --
> Sent from my phone. Please excuse my brevity.
>
> On March 9, 2016 10:14:25 AM PST, KMNanus <kmnanus at gmail.com> wrote:
> >I have a series of dates in  format 3-Oct, 10-Oct, 20-Oct, etc.
> >
> >I want to create a variable of just the month.  If I convert the date
> >to a character string, substr is ineffective because some of the dates
> >have 5 characters (3-Oct) and some have 6 (10-Oct).
> >
> >Is there a date function that accomplishes this easily?
> >
> >Ken
> >kmnanus at gmail.com
> >914-450-0816 (tel)
> >347-730-4813 (fax)
> >
> >
> >
> >______________________________________________
> >R-help at r-project.org mailing list -- To UNSUBSCRIBE and more, see
> >https://stat.ethz.ch/mailman/listinfo/r-help
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> >http://www.R-project.org/posting-guide.html
> >and provide commented, minimal, self-contained, reproducible code.
>
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>
> ______________________________________________
> R-help at r-project.org mailing list -- To UNSUBSCRIBE and more, see
> https://stat.ethz.ch/mailman/listinfo/r-help
> PLEASE do read the posting guide
> http://www.R-project.org/posting-guide.html
> and provide commented, minimal, self-contained, reproducible code.
>



-- 
Dan Dalthorp, PhD
USGS Forest and Rangeland Ecosystem Science Center
Forest Sciences Lab, Rm 189
3200 SW Jefferson Way
Corvallis, OR 97331
ph: 541-750-0953
ddalthorp at usgs.gov

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