[R] Extracting part of a factor
KMNanus
kmnanus at gmail.com
Sat Mar 5 03:31:32 CET 2016
Boris -
Boy, do I feel dumb - that’s exactly what I wanted. I’ve tried this every way I can think of without assigning the result to the original name of the data frame. I was trying to assign the result to a variable (test$place).
Can u pls explain to me why assigning the result to the new variable was wrong?
BTW, really appreciate your help.
Ken
kmnanus at gmail.com
914-450-0816 (tel)
347-730-4813 (fax)
> On Mar 4, 2016, at 9:21 PM, Boris Steipe <boris.steipe at utoronto.ca> wrote:
>
> LOL you still need to assign it though:
>
>
> test <- mutate(test, place = factor(substr(test$subject,1,3)))
>
> str(test)
> 'data.frame': 6 obs. of 7 variables:
> $ subject: Factor w/ 6 levels "001-002","002-003",..: 1 2 3 4 5 6
> $ group : Factor w/ 2 levels "boys","girls": 1 1 1 2 2 2
> $ wk1 : int 2 7 9 5 2 1
> $ wk2 : int 3 6 4 7 6 4
> $ wk3 : int 4 5 6 8 3 7
> $ wk4 : int 5 4 1 9 8 4
> $ place : Factor w/ 6 levels "001","002","003",..: 1 2 3 4 5 6
>
>
> Without assigning the result, the output only gets printed to console. Remember that R is a functional language - a properly written R functio does not change anything, it only returns its result.
>
> :-)
>
>
> On Mar 4, 2016, at 4:13 PM, KMNanus <kmnanus at gmail.com> wrote:
>
>> If I call mutate this way - mutate(test, place = factor(substr(test$subject,1,3))), I get the same output as above but when I call class(test$place), I get NULL and the variable disappears.
>
More information about the R-help
mailing list