[R] Y in Kohonen xyf function
chalabi.elahe at yahoo.de
chalabi.elahe at yahoo.de
Wed Jun 22 21:00:55 CEST 2016
Dear Kimmo,
I already used df$speed[training] in df.xyf but I get this error:
Error in xyf(Xtraining,factor(df$speed[training]),grid=somgrid(5, :
NA/NaN/Inf in foreign function call (arg 1)
On Wednesday, June 22, 2016 3:48 AM, K. Elo <maillists at pp.inet.fi> wrote:
Hi again!
21.06.2016, 21:33, chalabi.elahe at yahoo.de wrote:
> Hi Kimmo, Thanks for your reply. I think now my problem is that I
> don't understand what does factor(df.classes[training]) do?
Sorry, my mistake, should habe been 'df$speed'. Please try the following:
--- snip ---
set.seed(7) training <- sample(nrow(df), 120)
Xtraining<- scale(df[training,])
Xtest <- scale(df[-training,], center = attr(Xtraining,
"scaled:center"), scale = attr(Xtraining,
"scaled:scale"))
xyf.df <- xyf(Xtraining, factor(df$speed[training]), grid =
somgrid(5, 5, "hexagonal"))
--- snip ---
HTH,
Kimmo
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