[R] Antwort: RE: Antwort: Re: Merging variables
PIKAL Petr
petr.pikal at precheza.cz
Thu Jun 9 09:47:38 CEST 2016
Hi
Thanks for example.
see in line
> -----Original Message-----
> From: G.Maubach at weinwolf.de [mailto:G.Maubach at weinwolf.de]
> Sent: Wednesday, June 8, 2016 3:56 PM
> To: PIKAL Petr <petr.pikal at precheza.cz>
> Cc: r-help at r-project.org
> Subject: Antwort: RE: [R] Antwort: Re: Merging variables
>
> Hi Petr,
>
> thanks for your reply.
>
> I prepared little example for you:
>
> -- cut --
>
> ds_temp_1 <-
> structure(list(
> CustId = c(1001, 1002, 1003, 1004, 1005, 1006),
> CustName = c("Miller", "Smith", "Doe", "White", "Black",
> "Nobody"),
> sales = c(100, 500, 300, 50, 700, 10)
> ),
> .Names = c("CustId",
> "CustName", "sales"), row.names = c(NA, 6L), class =
> "data.frame")
>
> ds_temp_2 <-
> structure(
> list(
> CustId = c(1001, 1002, 1003),
> CustName = c("Miller",
> "Smith", "Doe"),
> CustGroup = c(1, 2, 3)
> ),
> .Names = c("CustId",
> "CustName", "CustGroup"),
> row.names = c(NA, 3L),
> class = "data.frame"
> )
>
> ds_merge <- merge(ds_temp_1, ds_temp_2,
> by.x = "CustId", all.x = TRUE,
> by.y = "CustId", all.y = FALSE)
>
> ds_merge
>
> -- cut --
>
> which gives
>
> ds_merge
> CustId CustName.x sales CustName.y CustGroup
> 1 1001 Miller 100 Miller 1
> 2 1002 Smith 500 Smith 2
> 3 1003 Doe 300 Doe 3
> 4 1004 White 50 <NA> NA
> 5 1005 Black 700 <NA> NA
> 6 1006 Nobody 10 <NA> NA
>
> where CustName is split into CustName.x and CustName.y.
>
> What I would like to have is:
>
> ds_merge
> CustId CustName sales CustGroup
> 1 1001 Miller 100 1
> 2 1002 Smith 500 2
> 3 1003 Doe 300 3
> 4 1004 White 50 NA
> 5 1005 Black 700 NA
> 6 1006 Nobody 10 NA
>
> That is CustName in a single variable cause the values within that variable are
> identical. I guess because of NA for some cases in ds_temp_2 R generates
> CustName.x and CustName.y.
Do not guess, try or read help page. The behavior is due to fact that ***you** restricted merge only on cust id and resulting data frame cannot have columns with the same names.
ds_merge <- merge(ds_temp_1, ds_temp_2, all.x = TRUE, all.y = FALSE)
Regards
Petr
>
> Is there a simple way of merging a dataset and having R return a single
> variable is the values are identical or missing in either one of the datasets?
>
> Kind regards
>
> Georg
>
>
>
>
>
> Von: PIKAL Petr <petr.pikal at precheza.cz>
> An: "G.Maubach at weinwolf.de" <G.Maubach at weinwolf.de>,
> Kopie: "r-help at r-project.org" <r-help at r-project.org>
> Datum: 07.06.2016 13:11
> Betreff: RE: [R] Antwort: Re: Merging variables
>
>
>
> Hi
>
> > -----Original Message-----
> > From: R-help [mailto:r-help-bounces at r-project.org] On Behalf Of
> > G.Maubach at weinwolf.de
> > Sent: Tuesday, June 7, 2016 8:19 AM
> > To: Michael Dewey <lists at dewey.myzen.co.uk>
> > Cc: r-help at r-project.org
> > Subject: [R] Antwort: Re: Merging variables
> >
> > Hi Michael,
> >
> > yes, I was astonished about this behaviour either. I have worked with
> SPSS a
> > lot - and that works different.
>
> If you want to join two data frames by common names you can use use
>
> merge(dat1, dat2, ....)
>
> without specifing by. From help page:
>
> By default the data frames are merged on the columns with names they both
> have, but separate specifications of the columns can be given by by.x and
> by.y. The rows in the two data frames that match on the specified columns
> are extracted, and joined together.
>
> >
> > I would like to share some of my data. Can you tell me how I can dump
> > a dataset in a way that I can post it here as text?
>
> copy result of dput directly to your mail
>
> dput(dat)
> structure(list(hz = c(0, 25, 50), vykon = c(0, 11.6, 22.6)), .Names = c("hz",
> "vykon"), row.names = c(NA, -3L), class = "data.frame")
>
> We can use
>
> dat <- structure(list(hz = c(0, 25, 50), vykon = c(0, 11.6, 22.6)), .Names =
> c("hz", "vykon"), row.names = c(NA, -3L), class = "data.frame")
>
> to reconstruct the object.
>
> Regards
> Petr
>
> >
> > Kind regards
> >
> > Georg
> >
> >
> >
> >
> > Von: Michael Dewey <lists at dewey.myzen.co.uk>
> > An: G.Maubach at weinwolf.de, r-help at r-project.org,
> > Datum: 06.06.2016 15:45
> > Betreff: Re: [R] Merging variables
> >
> >
> >
> > X-Originating-<%= hostname %>-IP: [217.155.205.190]
> >
> > Dear Georg
> >
> > I find it a bit surprising that you end up with customer.x and
> customer.y. Can
> > you share with us a toy example of two data.frames which exhibit this
> > behaviour?
> >
> > On 06/06/2016 13:29, G.Maubach at weinwolf.de wrote:
> > > Hi All,
> > >
> > > I merged two datasets:
> > >
> > > ds_merge1 <- merge(x = ds_bw_customer_4_match, y =
> > > ds_zww_customer_4_match,
> > > by.x = "customer", by.y = "customer",
> > > all.x = TRUE, all.y = FALSE)
> > >
> > > R created a new dataset with the variables customer.x and customer.y.
> > > I would like to merge these two variable back together. I wrote a
> > > little function (code can be run) for it:
> > >
> > > -- cut --
> > >
> > > customer.x <- c("Miller", "Smith", NA, "Bird", NA)
> > > customer.y <- c("Miller", NA, "Doe", "Fish", NA)
> > > ds_test <- data.frame(customer.x, customer.y, stringsAsFactors =
> > > FALSE)
> > >
> > > t_merge_variables <-
> > > function(dataset,
> > > var1,
> > > var2,
> > > merged_var) {
> > >
> > > # Initialize
> > > dataset[[merged_var]] = rep(NA, nrow(dataset))
> > > dataset[["mismatch"]] = rep(NA, nrow(dataset))
> > >
> > > for (i in 1:nrow(dataset)) {
> > >
> > > # Check 1: var1 missing, var2 missing
> > > if (is.na(dataset[[i, var1]]) &
> > > is.na(dataset[[i, var2]])) {
> > > dataset[["mismatch"]] <- 1 # var1 & var2 are missing
> > >
> > > # Check 2: var1 filled, var2 missing
> > > } else if (!is.na(dataset[[i, var1]]) &
> > > is.na(dataset[[i, var2]])) {
> > > dataset[[i, merged_var]] <- dataset[[i, var1]]
> > > dataset[["mismatch"]] <- 0
> > >
> > > # Check 3: var1 missing, var2 filled
> > > } else if (is.na(dataset[[i, var1]]) &
> > > !is.na(dataset[i, var2])) {
> > > dataset[[i, merged_var]] <- dataset[[i, var2]]
> > > dataset[["mismatch"]] <- 0
> > >
> > > # Check 4: var1 == var2
> > > } else if (dataset[[i, var1]] == dataset[[i, var2]]) {
> > > dataset[[i, merged_var]] <- dataset[[i, var1]]
> > > dataset[["mismatch"]] <- 0
> > >
> > > # Leftover: var1 != var2
> > > } else {
> > > dataset[[i, merged_var]] <- NA
> > > dataset[["mismatch"]] <- 2 # var1 != var2
> > > } # end if
> > > } # end for
> > > return(dataset)
> > > }
> > >
> > > ds_var_merge1 <- t_merge_variables(dataset = ds_test,
> > > var1 = "customer.x",
> > > var2 = "customer.y",
> > > merged_var = "customer")
> > >
> > > ds_var_merge1
> > >
> > > -- cut --
> > >
> > > It is executed without error but delivers the wrong values in the
> > variable
> > > "mismatch". This variable is always 1 although it should be NA, 1 or
> > > 2 respectively.
> > >
> > > Can you tell me why the variable is not correctly set?
> > >
> > > Kind regards
> > >
> > > Georg
> > >
> > > ______________________________________________
> > > R-help at r-project.org mailing list -- To UNSUBSCRIBE and more, see
> > > https://stat.ethz.ch/mailman/listinfo/r-help
> > > PLEASE do read the posting guide
> > http://www.R-project.org/posting-guide.html
> > > and provide commented, minimal, self-contained, reproducible code.
> > >
> >
> > --
> > Michael
> > http://www.dewey.myzen.co.uk/home.html
> >
> > ______________________________________________
> > R-help at r-project.org mailing list -- To UNSUBSCRIBE and more, see
> > https://stat.ethz.ch/mailman/listinfo/r-help
> > PLEASE do read the posting guide http://www.R-project.org/posting-
> > guide.html and provide commented, minimal, self-contained,
> > reproducible code.
>
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