[R] Merging variables
David Winsemius
dwinsemius at comcast.net
Mon Jun 6 14:48:11 CEST 2016
You loop through each
Sent from my iPhone
> On Jun 6, 2016, at 8:29 AM, G.Maubach at weinwolf.de wrote:
>
> Hi All,
>
> I merged two datasets:
>
> ds_merge1 <- merge(x = ds_bw_customer_4_match, y =
> ds_zww_customer_4_match,
> by.x = "customer", by.y = "customer",
> all.x = TRUE, all.y = FALSE)
>
> R created a new dataset with the variables customer.x and customer.y. I
> would like to merge these two variable back together. I wrote a little
> function (code can be run) for it:
>
> -- cut --
>
> customer.x <- c("Miller", "Smith", NA, "Bird", NA)
> customer.y <- c("Miller", NA, "Doe", "Fish", NA)
> ds_test <- data.frame(customer.x, customer.y, stringsAsFactors = FALSE)
>
> t_merge_variables <-
> function(dataset,
> var1,
> var2,
> merged_var) {
>
> # Initialize
> dataset[[merged_var]] = rep(NA, nrow(dataset))
> dataset[["mismatch"]] = rep(NA, nrow(dataset))
>
> for (i in 1:nrow(dataset)) {
>
> # Check 1: var1 missing, var2 missing
> if (is.na(dataset[[i, var1]]) &
> is.na(dataset[[i, var2]])) {
> dataset[["mismatch"]] <- 1 # var1 & var2 are missing
>
> # Check 2: var1 filled, var2 missing
> } else if (!is.na(dataset[[i, var1]]) &
> is.na(dataset[[i, var2]])) {
> dataset[[i, merged_var]] <- dataset[[i, var1]]
> dataset[["mismatch"]] <- 0
>
> # Check 3: var1 missing, var2 filled
> } else if (is.na(dataset[[i, var1]]) &
> !is.na(dataset[i, var2])) {
> dataset[[i, merged_var]] <- dataset[[i, var2]]
> dataset[["mismatch"]] <- 0
>
> # Check 4: var1 == var2
> } else if (dataset[[i, var1]] == dataset[[i, var2]]) {
> dataset[[i, merged_var]] <- dataset[[i, var1]]
> dataset[["mismatch"]] <- 0
>
> # Leftover: var1 != var2
> } else {
> dataset[[i, merged_var]] <- NA
> dataset[["mismatch"]] <- 2 # var1 != var2
> } # end if
> } # end for
> return(dataset)
> }
>
> ds_var_merge1 <- t_merge_variables(dataset = ds_test,
> var1 = "customer.x",
> var2 = "customer.y",
> merged_var = "customer")
>
> ds_var_merge1
>
> -- cut --
>
> It is executed without error but delivers the wrong values in the variable
> "mismatch". This variable is always 1 although it should be NA, 1 or 2
> respectively.
>
> Can you tell me why the variable is not correctly set?
>
> Kind regards
>
> Georg
>
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