[R] R - Populate Another Variable Based on Multiple Conditions | For a Large Dataset
Kevin Wamae
KWamae at kemri-wellcome.org
Sat Jul 2 18:40:11 CEST 2016
Hi Jennifer, i attached a file with a snapshot of the dataset..it must have failed to attach, shall I send another?
K. Kariuki
------ Original message ------
From: Jeff Newmiller
Date: 02/07/2016 19:37
To: Kevin Wamae;R | Help Nabble;
Subject:Re: [R] R - Populate Another Variable Based on Multiple Conditions | For a Large Dataset
I can understand you not wanting to supply your actual data online, but only you know what your data looks like so only you can create a simulated data set that we could show you how to work with.
--
Sent from my phone. Please excuse my brevity.
On July 2, 2016 2:57:39 AM PDT, Kevin Wamae <KWamae at kemri-wellcome.org> wrote:
>I have a drug-trial study dataset (attached image).
>
>Since its a large and complex dataset (at least to me) and I hope to be
>as clear as possible with my question.
>The dataset is from a study where individuals are given drugs and
>followed up over a period spanning two consecutive years. Individuals
>do not start treatment on the same day and once they start, the
>variable "drug-admin" is marked "x" as well as the time they stop
>treatment in the following year.
>There exists another variable, "study_id", that I hope to populate as
>can be seen in the dataset, with the following conditions:
>
>For every individual
>• if the individual has entries that show they received drugs both
>on the start and end date (marked with the "x")
>• if the start of drug administration falls in month == 2 | 3 and
>end of administration falls in month == 2 | 4
>• then, using the date that marks the start of drug administration,
>populate the variable _"study_id"_ in all the rows that fall within the
>timeframe that the individual was given drugs but excluding the end of
>drug administration.
>I have tried my level best and while I have explored several examples
>online, I haven't managed to solve this. The dataset contains close to
>6000 individuals spanning 10 years and my best bet was to use a loop
>which keeps crushing R after running for close to 30min. I have also
>read that dplyr may do the job but my attempts have been in vain.
>
>sample code
>-------------------------------------------------------------------------------------------------------------------------------------------------------------------
>individual <- unique (df$ID) #vector of individuals
>datalength <- dim(df)[1] #number of rows in dataframe
>
>for (i in 1:length(individual)) {
> for (j in 1:datalength) {
>start_admin <- df[(df$year == 2007] & df$drug_admin == "x" & c(df$month
>== 2 | df$month == 3),1] #capture date of start
>end_admin <- df[(df$year == 2008] & df$drug_admin == "x" & c(df$month
>== 2 | df$month == 4),1] #capture date of end
>
>if(df[datalength,1] == individual(i) & df[datalength,2] >= start_admin
>& df[datalength,2] < end_admin) {
>df[datalength,6] <- start_admin #populate respective row if condition
>is met
> }
> }
> }
>
>-------------------------------------------------------------------------------------------------------------------------------------------------------------------
>
>Above is the code that keeps failing..
>
>Any help is highly appreciated....
>
>
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