[R] Grep Help

[Boris Steipe]

I see numerous backticks in your code, not quotes. "`" and "'" are not the same. Backticks are not string delimiters.
As for valid names: look at the help page for make.names().


HTH,
Boris



On Feb 22, 2016, at 1:32 PM, Burhan ul haq <ulhaqz at gmail.com> wrote:

> Hi,
> 
> # 1) I have read in a CSV file
> 
> df = read.csv(file="GiftCards - v1.csv",stringsAsFactors=FALSE)
> head(df)
> str(df)
> 
> # 2) converted to a tbl_df
> df2 = tbl_df(df)
> 
> # 3) fixed the names to remove leading "X" character
> n = names(df2)
> n2 = gsub(pattern="^\\w","\\1",n)
> names(df2) = n2
> 
> # 4) somehow the col names are character strings, requiring me to use
> quotes:
> df2$`2006` instead of df2$2006 # ---> PROBLEM 1
> 
> 
> # 5) I need to remove the leading $ sign followed by spaces to extract
> values. The problem is # it could be a two or three digit number. I am able
> to retrieve two digits correctly, but miss # out on the leading third digit.
> df2$`2006`= gsub("^(.+)([0-9]{2,3}\\.[0-9]{2})","\\2",df2$`2006`) # -->
> Problem 2
> 
> # 6) dump for the data frame
> 
> df2 <-
> structure(list(`2006` = structure(c(3L, 2L, 1L), .Label = c("$
> 24.81",
> "$     39.16", "$   146.20"), class = "factor"), `2007` = structure(c(3L,
> 2L, 1L), .Label = c("$       26.25", "$     41.95", "$   156.24"
> ), class = "factor"), `2008` = structure(c(3L, 2L, 1L), .Label = c("$
> 24.92",
> "$     40.54", "$   147.33"), class = "factor"), `2009` = structure(c(3L,
> 2L, 1L), .Label = c("$       23.63", "$     39.80", "$   139.91"
> ), class = "factor"), `2010` = structure(c(3L, 2L, 1L), .Label = c("$
> 24.78",
> "$     41.48", "$   145.61"), class = "factor"), `2011` = structure(c(3L,
> 2L, 1L), .Label = c("$       27.80", "$     43.23", "$   155.43"
> ), class = "factor"), `2012` = structure(c(3L, 2L, 1L), .Label = c("$
> 28.79",
> "$     43.75", "$   156.86"), class = "factor"), `2013` = structure(c(3L,
> 2L, 1L), .Label = c("$       29.80", "$     45.16", "$   163.16"
> ), class = "factor")), .Names = c("2006", "2007", "2008", "2009",
> "2010", "2011", "2012", "2013"), class = c("tbl_df", "tbl", "data.frame"
> ), row.names = c(NA, -3L))
> 
> 
> 
> Thanks for the help
> 
> 
> Br /
> 
> 	[[alternative HTML version deleted]]
> 
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