[R] about data format in R
Rui Barradas
ruipbarradas at sapo.pt
Fri Dec 30 19:56:12 CET 2016
Hello,
What I did was:
DF <- read.table(text = "
date evap precip intercept
10/01/1995-00:00:00 1.5 2 0.2
10/01/1995-12:00:00 1.7 2.2 0.1
10/02/1995-00:00:00 1.5 1.8 0.3
", header = TRUE, stringsAsFactors = FALSE)
str(DF)
DF$date <- as.POSIXct(DF$date, format = "%m/%d/%Y-%H:%M:%S")
str(DF)
And it worked with no errors.
Rui Barradas
Em 30-12-2016 18:47, Sarah Goslee escreveu:
> Probably you need to use
>
> file1 <- read.table('df', header=TRUE, stringsAsFactors=FALSE)
>
> str(file1)
>
> generally shows you all sorts of useful things about the file you have
> just imported into R.
>
> Sarah
>
> On Fri, Dec 30, 2016 at 1:37 PM, lily li <chocold12 at gmail.com> wrote:
>> Hi Rui,
>>
>> Thanks for your reply. When I read in data using my code, the first column
>> ranges from 0 to 1. So when I use the code you wrote, it shows the error
>> message:
>> Error in as.POSIXct.numeric(DF$Date, format = "%m/%d/%Y-%H:%M:%S") :
>> 'origin' must be supplied
>>
>>
>> On Fri, Dec 30, 2016 at 11:23 AM, Rui Barradas <ruipbarradas at sapo.pt> wrote:
>>
>>> Hello,
>>>
>>> Have you tried
>>>
>>> df$date <- as.POSIXct(dat$date, format = "%m/%d/%Y-%H:%M:%S")
>>>
>>> ?
>>>
>>> Hope this helps,
>>>
>>> Rui Barradas
>>>
>>>
>>>
>>> Em 30-12-2016 17:40, lily li escreveu:
>>>
>>>> Hi R users,
>>>>
>>>> I'm trying to read in data, and then plot time series data. However, I
>>>> have
>>>> some problems. In my dataset, the first column represents time, and in the
>>>> format:
>>>> mm/dd/yyyy-hr:min:sec; For example, 10/01/1995-00:00:00,
>>>> 10/01/1995-06:00:00, etc.
>>>>
>>>> df:
>>>> date evap precip intercept
>>>> 10/01/1995-00:00:00 1.5 2 0.2
>>>> 10/01/1995-12:00:00 1.7 2.2 0.1
>>>> 10/02/1995-00:00:00 1.5 1.8 0.3
>>>> ...
>>>>
>>>> My code is like this
>>>> file1 = read.table('df', head=T)
>>>>
>>>> When I read in data, I found that it read incorrectly. How to format when
>>>> read in data? Thanks.
>>>>
>
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