[R] how to use AND in grepl
William Dunlap
wdunlap at tibco.com
Sat Apr 30 23:55:00 CEST 2016
Your code looks fine to me. What did t2pd look like?
I tried reproducing the problem in R-3.2.4(Revised) and everything worked
(although the output of str() looked a bit different - perhaps you have an
old version of R)
> df <- data.frame(TE=1:10, TR=101:110,
Command=c("pd_local_abdomen_t2","knee_pd_t1_localize","PD_localize_tre_t2","t2_localize_PD")[rep(1:4,len=10)])
> str(df)
'data.frame': 10 obs. of 3 variables:
$ TE : int 1 2 3 4 5 6 7 8 9 10
$ TR : int 101 102 103 104 105 106 107 108 109 110
$ Command: Factor w/ 4 levels "knee_pd_t1_localize",..: 2 1 3 4 2 1 3 4 2 1
> subset(df,grepl("t2",Command) & grepl("pd",Command))
TE TR Command
1 1 101 pd_local_abdomen_t2
5 5 105 pd_local_abdomen_t2
9 9 109 pd_local_abdomen_t2
> subset(df,grepl("t2",Command,ignore.case=TRUE) &
grepl("pd",Command,ignore.case=TRUE))
TE TR Command
1 1 101 pd_local_abdomen_t2
3 3 103 PD_localize_tre_t2
4 4 104 t2_localize_PD
5 5 105 pd_local_abdomen_t2
7 7 107 PD_localize_tre_t2
8 8 108 t2_localize_PD
9 9 109 pd_local_abdomen_t2
Bill Dunlap
TIBCO Software
wdunlap tibco.com
On Sat, Apr 30, 2016 at 2:38 PM, ch.elahe via R-help <r-help at r-project.org>
wrote:
> Hi all,
>
> I have one factor variable in my df and I want to extract the names from
> it which contain both "t2" and "pd":
>
> 'data.frame': 36919 obs. of 162 variables
> $TE :int 38,41,11,52,48,75,.....
> $TR :int 100,210,548,546,.....
> $Command :factor W/2229 levels
> "_localize_PD","_localize_tre_t2","_abdomen_t1_seq","knee_pd_t1_localize","pd_local_abdomen_t2"...
>
> I have tried this but I did not get result:
>
> t2pd=subset(df,grepl("t2",Command) & grepl("pd",Command))
>
>
> does anyone know how to apply AND in grepl?
>
> Thanks
> Elahe
>
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