[R] groups Rank

Mon Sep 7 11:29:21 CEST 2015

Hi

OK, thanks for sending dput result.

I am still not sure what exactly you want. Using ?ave you can get result of x/max(x)

dat$prob <- ave(dat$value, paste(dat$id, dat$i), FUN= function(x) x/max(x))

however in case max(x) is zero the result is NA

You can change it to zero

dat$prob[is.nan(dat$prob)] <- 0

and compute rank value by similar process.

dat$rankvalue <- ave(dat$prob, paste(dat$id, dat$i), FUN = rank)

But I am not sure if this is the desired result.

Cheers
Petr

> -----Original Message-----
> From: R-help [mailto:r-help-bounces at r-project.org] On Behalf Of Ragia
> Ibrahim
> Sent: Monday, September 07, 2015 10:12 AM
> To: Sarah Goslee; r-help at r-project.org
> Subject: Re: [R] groups Rank
>
> apology for re sending the Email, I changed the format to plain text as
> I have been advised the data  is as follow
>
> thanks Sarah,
> I used pdut, and here is the data as written on R..I attached the dput
> result structure(list(Measure_id = c(1, 1, 1, 1, 1, 2, 2, 2, 3, 3, 3,
> 3, 1, 1, 1, 1, 1, 2, 2, 2, 3, 3, 3, 3, 1, 1, 1, 1, 1, 2, 2, 2, 3, 3, 3,
> 3, 1, 1, 1, 1, 1, 2, 2, 2, 3, 3, 3, 3), i = c(5, 5, 5, 5, 5, 5, 5, 5,
> 5, 5, 5, 5, 5, 5, 5, 5, 5, 5, 5, 5, 5, 5, 5, 5, 7, 7, 7, 7, 7, 7, 7, 7,
> 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7), j = c(1, 1, 1, 1, 1,
> 1, 1, 1, 1, 1, 1, 1, 2, 2, 2, 2, 2, 2, 2, 2, 2, 2, 2, 2, 3, 3, 3, 3, 3,
> 3, 3, 3, 3, 3, 3, 3, 5, 5, 5, 5, 5, 5, 5, 5, 5, 5, 5, 5), id = c(1, 2,
> 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12,
> 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10,
> 11, 12), value = c(2, 1.5, 0, 0, 1, 0.5, 0, 0, 0, 0, 0.5, 2, 2, 1.5, 0,
> 1, 2, 0, 0.5, 1.44269504088896, 0, 0, 0, 0, 1, 1.5, 0, 0, 1, 0, 0, 0,
> 0, 0, 0, 0, 1, 2, 0, 0, 1, 0, 0, 0, 0, 0, 0, 0)), .Names =
> c("Measure_id", "i", "j", "id", "value"), row.names = c(NA, 48L), class
> = "data.frame")
>
> the data  is as follow  :
>
>    Measure_id i j id value
> 1           1 5 1  1   2.0
> 2           1 5 2  1   2.0
> 3           1 5 1  2   1.5
> 4           1 5 2  2   1.5
> 5           1 5 1  3   0.0
> 6           1 5 2  3   0.0
> 7           1 5 1  4   0.0
> 8           1 5 2  4   1.0
> 9           1 5 1  5   1.0
> 10          1 5 2  5   2.0
> ..        ... . . ..   ...
> I want to add a probability column,  the prob column depends on id
> grouped by for each i the rank will be current (value / max value ) for
> the same id for specific i, it would be
>
>  Measure_id i j id value    prob
> 1           1 5 1  1   2.0          2/2
> 2           1 5 2  1   2.0          2/2
> 3           1 5 1  2   1.5          1.5/1.5
> 4           1 5 2  2   1.5          1.5/1.5
> 5           1 5 1  3   0.0          0
> 6           1 5 2  3   0.0          0
> 7           1 5 1  4   0.0          0/1
> 8           1 5 2  4   1.0          1/1
> 9           1 5 1  5   1.0          1/2
> 10          1 5 2  5   2.0          2/3
> ..        ... . . ..   ...
>
> then I want to add a rank column that rank regarding probability, if
> the probability equal they took the same rank for the same id belongs
> to the same i, otherwize lower probability took higher rank for examole
> if we have three values for i=7 and for the three values the id is 1
> and the probability is ( .2,.4,.5) the rank should be 3,2,1
>
>
>
> I looked at aggregate and dplyr...should I use for loop and subset each
> i and id rows do calculations and then group them again ??
> is there easier way?
>
> replying  highly appreciated
> >
> >
> >
> >> Date: Sun, 6 Sep 2015 19:02:02 -0400
> >> Subject: Re: [R] groups Rank
> >> From: sarah.goslee at gmail.com
> >> To: ragia11 at hotmail.com
> >> CC: r-help at r-project.org
> >>
> >> Please use dput() to provide data, rather than expecting people to
> >> open random attachments. Besides, there are multiple options for
> >> getting data into R, and we need to know exactly what you did.
> dput()
> >> is faster and easier.
> >>
> >> What have you tried? Did you look at aggregate() as I suggested?
> >>
> >> Sarah
> >>
> >> On Sat, Sep 5, 2015 at 10:44 AM, Ragia Ibrahim <ragia11 at hotmail.com>
> wrote:
> >>> thanks for replying, I attached the data frame for source "i" I
> want
> >>> to sum the values and get the max value then add a new column
> called
> >>> rank . That new column cell value for each source i and for
> specific
> >>> id would be (value/max value) * count of rows that have the same
> >>> criteria "same i and same id"
> >>>
> >>> many thanks
> >>> Ragia
> >>>
> >>>> Date: Fri, 4 Sep 2015 10:19:35 -0400
> >>>> Subject: Re: [R] groups Rank
> >>>> From: sarah.goslee at gmail.com
> >>>> To: ragia11 at hotmail.com
> >>>> CC: r-help at r-project.org
> >>>>
> >>>> Hi Ragia,
> >>>>
> >>>> I can't make out your data or desired result, but it sounds like
> >>>> aggregate() might get you started. If you need more help, please
> >>>> repost your data using dput() and do NOT post in HTML so that we
> >>>> can see what your desired result looks like.
> >>>>
> >>>> Sarah
> >>>>
> >>>> On Fri, Sep 4, 2015 at 10:12 AM, Ragia Ibrahim
> >>>> <ragia11 at hotmail.com>
> >>>> wrote:
> >>>>> Dear Group,kinldy, I have the following data frame df id value1 1
> >>>>> 4 2 1 4 3 1 6 4 1 6 5 2 1.5 6 2 2.5 7 2 2.5 8 2 2.5
> >>>>>
> >>>>> add rank column regarding id coulmn where rank for the highest
> >>>>> value would be 1, others rank would be the (value/ value of
> >>>>> heighest)/
> > number of
> >>>>> rows that took the same value
> >>>>> thus the data frame should be
> >>>>> id value Rank1 1 4 0.332 1 4 0.333 1 6 0.54 1 6 0.55 2 1.5 0.6 6
> 2
> >>>>> 2.5
> >>>>> 0.337 2 2.5 0.338 2 2.5 0.33
> >>>>>
> >>>>> how to reach this resultthanks in advanceRagia [[alternative HTML
> >>>>> version deleted]]
> >>>>>
>
> ______________________________________________
> R-help at r-project.org mailing list -- To UNSUBSCRIBE and more, see
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> and provide commented, minimal, self-contained, reproducible code.

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