[R] Looking for a more elegant solution than a loop

[William Dunlap]

> identical(as.list(x), xz)
[1] TRUE
Bill Dunlap
TIBCO Software
wdunlap tibco.com


On Mon, Oct 26, 2015 at 6:31 PM, Erin Hodgess <erinm.hodgess at gmail.com> wrote:
> Hello!
>
> The following (which is a toy example) works fine, but I wonder if there is
> a better or more elegant way than to do the loop:
>
>  xz <- vector("list",length=4)
>  x <- 6:9
>  for(i in 1:4)xz[[i]] <- x[i]
>  xz
> [[1]]
> [1] 6
>
> [[2]]
> [1] 7
>
> [[3]]
> [1] 8
>
> [[4]]
> [1] 9
>
> This does exactly what I want, but the "for" loop seems out of place.
> Maybe not.
>
> Thanks,
> Sincerely
> Erin
>
>
> --
> Erin Hodgess
> Associate Professor
> Department of Mathematical and Statistics
> University of Houston - Downtown
> mailto: erinm.hodgess at gmail.com
>
>         [[alternative HTML version deleted]]
>
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