[R] error with seq() used in for loop

[Maram SAlem]

Thanks Berend

On 11 October 2015 at 14:10, Berend Hasselman <bhh at xs4all.nl> wrote:

>
> > On 11 Oct 2015, at 13:52, Maram SAlem <marammagdysalem at gmail.com> wrote:
> >
> > Dear All,
> > I have a question concerning the seq() function arguments when used in a
> > for() loop.
> > I'll simplify this question to make it more clear. Suppose I have a
> > (5*3)matrix s (for ex.) and I need to write a function with  for() loop,
> in
> > each step of the loop I need to generate a sequence whose upper limit is
> > the ith element of the first row of s, then put the resulting sequences
> in
> > a list. I used the following simple code (I've only included the first
> part
> > of the function)
> >
> >
> >> s<-matrix(c(1,0,1,0,1,1,0,0,1,0,0,0,0,0,1),nrow=5,byrow=TRUE)
> >> simpfun<- function (x,n,m,p,alpha,beta)
> > + {
> > + LD<-list()
> > + for (i in 1:m-1)
> > + {
> > + LD[[i]]<-seq(0,x[i],1)
> > + }
> > + print(LD)
> > + }
> >> mk<-simpfun(s[1,],n=6,m=4,p=0.3)
> > Error in seq.default(0, x[i], 1) : 'to' must be of length 1
> >
> > Although x is supposed to be the vector
> > 1 0 1
> > and thus x[1]=1, x[2]=0,x[3]=1.
> > So I don't get why the error "Error in seq.default(0, x[i], 1) : 'to'
> must
> > be of length 1" occurs in the first place.
>
>
> Use
>
> for (i in 1:(m-1))
>
> in stead of what you put in the function.
> Read the section “Generating regular sequences” in the "An Introduction to
> R“ manual.
>
> Berend
>
>
>

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