[R] Measure the frequencies of pairs in a matrix
David L Carlson
dcarlson at tamu.edu
Wed Oct 7 17:30:45 CEST 2015
As with Boris, I'm not sure what you are looking for, but this may help
> # To get all possibilities, create a grid
> grd <- expand.grid(0:9, 0:9)
> # Extract those with smaller first column values
> grd <- grd[grd$Var1 <= grd$Var2,]
> # Tabulate after pasting first and second column
> grd2 <- data.frame(table(apply(grd, 1, paste0, collapse=" - ")))
>
> # Combine the two tables and subtract 1 to get rid of the counts from grd2$Freq
> dta2 <- rbind(grd2, dta)
> freqs <- data.frame(xtabs(Freq~Var1, dta2) - 1)
> str(freqs)
'data.frame': 55 obs. of 2 variables:
$ Var1: Factor w/ 55 levels "0 - 0","0 - 1",..: 1 2 3 4 5 6 7 8 9 10 ...
$ Freq: num 0 0 0 0 0 0 0 0 0 0 ...
> freqs[c(40:50), ]
Var1 Freq
40 4 - 9 0
41 5 - 5 2
42 5 - 6 10
43 5 - 7 4
44 5 - 8 0
45 5 - 9 0
46 6 - 6 0
47 6 - 7 2
48 6 - 8 0
49 6 - 9 0
50 7 - 7 0
-------------------------------------
David L Carlson
Department of Anthropology
Texas A&M University
College Station, TX 77840-4352
-----Original Message-----
From: R-help [mailto:r-help-bounces at r-project.org] On Behalf Of Boris Steipe
Sent: Wednesday, October 7, 2015 8:10 AM
To: Hermann Norpois
Cc: r-help
Subject: Re: [R] Measure the frequencies of pairs in a matrix
Still not sure I understand. But here is what I think you might mean:
# Your data
mat <- structure(c(5, 6, 5, 5, 4, 3, 6, 7, 4, 7, 5, 5, 5, 5, 6, 5, 5,
4, 3, 6, 7, 4, 7, 5, 5, 5, 6, 5, 4, 5, 5, 7, 5, 6, 3, 5, 6, 7,
6, 6, 5, 4, 5, 5, 7, 5, 6, 3, 5, 6, 7, 6), .Dim = c(26L, 2L))
# Create a square matrix with enough space to have an element for each pair. Since
# order is not important, only the upper triangle is used. If the matrix is
# large and sparse, a different approach might be needed.
freq <- matrix(numeric(max(mat) * max(mat)), nrow = max(mat), ncol = max(mat))
# Loop over your input
for (i in 1:nrow(mat)) {
# Sort the elements of a row by size.
x <- sort(mat[i,])
# Increment the corresponding element of the frequency matrix
freq[x[1], x[2]] <- freq[x[1], x[2]] + 1
}
freq
Cheers,
B.
On Oct 7, 2015, at 1:17 AM, Hermann Norpois <hnorpois at gmail.com> wrote:
> Ok, this was misleading. And was not that important. My result matrix should look like this:
>
> 1 2 3 4 5 6 7 ...
> 1 p1 p2
> 2 p
> 3
> 4
>
> p1 etc are the frequencies of the combinations
>
> 1 and 2 for instance do not appear in my example. So the values would be zero. Actually, this part is not too important. I would be happy enough to solve the challenge with the frequencies of the pairs.
> Thanks Hermann
>
> 2015-10-07 2:40 GMT+02:00 Boris Steipe <boris.steipe at utoronto.ca>:
> Since order is not important to you, you can order your pairs (e.g. decreasing) before compiling the frequencies.
> But I don't understand the second part about values "that do not appear in the matrix". Do you mean you want to assess all combinations? If that's the case I would think about a hash table or other indexed data structure, rather than iterating through a matrix.
>
>
> B.
>
>
>
> On Oct 6, 2015, at 4:59 PM, Hermann Norpois <hnorpois at gmail.com> wrote:
>
> > Hello,
> >
> > I have a matrix mat (see dput(mat))
> >
> >> mat
> > [,1] [,2]
> > [1,] 5 6
> > [2,] 6 5
> > [3,] 5 4
> > [4,] 5 5
> > ....
> >
> > I want the frequencies of the pairs in a new matrix, whereas the
> > combination 5 and 6 is the same as 6 and 5 (see the first two rows of mat).
> > In other words: What is the probability of each combination (each row)
> > ignoring the order in the combination. As a result I would like to have a
> > matrix that includes rows and cols 0, 1, 2 ... max (mat) that do not appear
> > in my matrix.
> >
> > dput (mat)
> > structure(c(5, 6, 5, 5, 4, 3, 6, 7, 4, 7, 5, 5, 5, 5, 6, 5, 5,
> > 4, 3, 6, 7, 4, 7, 5, 5, 5, 6, 5, 4, 5, 5, 7, 5, 6, 3, 5, 6, 7,
> > 6, 6, 5, 4, 5, 5, 7, 5, 6, 3, 5, 6, 7, 6), .Dim = c(26L, 2L))
> >
> > Thanks
> > Hermann
> >
> > [[alternative HTML version deleted]]
> >
> > ______________________________________________
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